Holt Mcdougal Larson Pre-algebra: Student Edition 2012
1st Edition
ISBN:9780547587776
Author:HOLT MCDOUGAL
Publisher:HOLT MCDOUGAL
Chapter9: Real Numbers And Right Triangles
Section9.5: The Distance And Midpoint Formulas
Problem 2C
Related questions
Question
![**Title: Identifying Points on a Line Equation**
**Question:**
Two points that lie on the line \(5x - 3y = 15\) are \((3, 0)\).
**Options:**
- ( ) \((5, -3)\)
- ( ) \((5, 3)\)
- ( ) \((0, 5)\)
- ( ) \((0, -5)\)
**Explanation:**
To determine which points lie on the given line, we substitute the coordinates of each point into the equation \(5x - 3y = 15\) and check if the equation holds true:
1. **For \((5, -3)\):**
\[
5(5) - 3(-3) = 25 + 9 = 34 \neq 15
\]
This point does not lie on the line.
2. **For \((5, 3)\):**
\[
5(5) - 3(3) = 25 - 9 = 16 \neq 15
\]
This point does not lie on the line.
3. **For \((0, 5)\):**
\[
5(0) - 3(5) = 0 - 15 = -15 \neq 15
\]
This point does not lie on the line.
4. **For \((0, -5)\):**
\[
5(0) - 3(-5) = 0 + 15 = 15
\]
This point lies on the line.
Therefore, the correct point from the options provided that lies on the line \(5x - 3y = 15\) alongside \((3, 0)\) is \((0, -5)\).](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2F4c4afdc6-ca8a-4b2a-8330-6d75607762e2%2F9001c761-52f2-4b4e-83b9-1c314e4616c8%2Fick132_processed.jpeg&w=3840&q=75)
Transcribed Image Text:**Title: Identifying Points on a Line Equation**
**Question:**
Two points that lie on the line \(5x - 3y = 15\) are \((3, 0)\).
**Options:**
- ( ) \((5, -3)\)
- ( ) \((5, 3)\)
- ( ) \((0, 5)\)
- ( ) \((0, -5)\)
**Explanation:**
To determine which points lie on the given line, we substitute the coordinates of each point into the equation \(5x - 3y = 15\) and check if the equation holds true:
1. **For \((5, -3)\):**
\[
5(5) - 3(-3) = 25 + 9 = 34 \neq 15
\]
This point does not lie on the line.
2. **For \((5, 3)\):**
\[
5(5) - 3(3) = 25 - 9 = 16 \neq 15
\]
This point does not lie on the line.
3. **For \((0, 5)\):**
\[
5(0) - 3(5) = 0 - 15 = -15 \neq 15
\]
This point does not lie on the line.
4. **For \((0, -5)\):**
\[
5(0) - 3(-5) = 0 + 15 = 15
\]
This point lies on the line.
Therefore, the correct point from the options provided that lies on the line \(5x - 3y = 15\) alongside \((3, 0)\) is \((0, -5)\).
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