The incubation period refers to the number of days between being in contact with an infected personand actually showing symptoms of being infected. Health care professionals say that the meanincubation period of COVID-19 is 12 days with a standard deviation of 2 days. This accounts for the14-day quarantine period.With the recent upsurge of infections due to the different variants of the virus, a group of researcherssurveyed 100 confirmed cases and found that the mean incubation period is 11.5 days. Is there enoughevidence to show that the mean incubation period has actually changed?Which of these significance levels will lead to a rejection of the Ho?(Aa>0.06%a<0.06%α< 1%a > 5%

To decide: Which of these significance level lead to rejection of Null hypothesis

Answered: The incubation period refers to the…

MATLAB: An Introduction with Applications

6th Edition

ISBN:9781119256830

Author:Amos Gilat

Publisher:Amos Gilat

Chapter1: Starting With Matlab

Section: Chapter Questions

Problem 1P

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One way to check on how representative a survey is of the population from which it was drawn is to compare various characteristics of the sample with the population characteristics. A typical variable used for this purpose is age. The GSS 2018 found a mean age of 48.69 and a standard deviation of 17.99 for its sample of 1,495 American adults. Assume that we know from census data that the mean age of all American adults is 37.80. What is the research and the null hypotheses for a two-tailed test of means, calculate the t statistic and test the null hypothesis at the .001 significance level, and what is the decision about the null hypothesis?
A researcher suspects the mean trough (the lowest dosage of medication required to see clinical improvement of symptoms) level for a medication used to treat arthritis is higher than was previously reported in other studies. If previous studies found the mean trough level of the population to be 3.7 micrograms/mL, and the researcher conducts a study among 93 newly diagnosed arthritis patients and finds the mean trough to be 6.1 micrograms/mL with a standard deviation of 2.4 micrograms/mL, for a level of significance of 1%, what should the researcher’s decision rule look like?
An elementary school class ran 1 mile with a mean of 11 minutes and a standard deviation of 3minutes. Rachel, a student in the class, ran 1 mile in 8 minutes. A junior high school class ran 1mile with a mean of 9 minutes and a standard deviation of 2 minutes. Kenji, a student in the class,ran 1 mile in 8.5 minutes. A high school class ran 1 mile with a mean of 7 minutes and a standarddeviation of 4 minutes. Nedda, a student in the class, ran 1 mile in 8 minutes. a. Why is Kenji considered a better runner than Nedda, even though Nedda ran faster than he? b. Who is the fastest runner with respect to his or her class? Explain why
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Consumer agencies claim that the mean lifespan of a dishwasher is 9.5 years. Your company manufacturers dishwasher and you have been asked to see if this claim is true. You randomly survey 20 households who have recently purchased a dishwasher and ask them how long their previous dishwashers lasted and you calculate a mean of 8.9 years with a standard deviation of 3.1. Is the consumer agency’s claim that a dishwasher lasts 9.5 year correct? What is the p-value for this claim? Consumer agencies claim that the mean lifespan of a dishwasher is 9.5 years. Your company manufacturers dishwasher and you have been asked to see if this claim is true. You randomly survey 20 households who have recently purchased a dishwasher and ask them how long their previous dishwashers lasted and you calculate a mean of 8.9 years with a standard deviation of 3.1. Is the consumer agency’s claim that a dishwasher lasts 9.5 year correct? What is the p-value for this claim? 0.8012 0.1988 0.3975 -0.8656
A researcher suspects the mean trough (the lowest dosage of medication required to see clinical improvement of symptoms) level for a medication used to treat arthritis is higher than was previously reported in other studies. If previous studies found the mean trough level of the population to be 3.7 micrograms/mL, and the researcher conducts a study among 93 newly diagnosed arthritis patients and finds the mean trough to be 6.1 micrograms/mL with a standard deviation of 2.4 micrograms/mL, for a level of significance of 1%, what should the researcher’s decision rule look like? Reject H0 if z is less than or equal to –2.326. Reject H0 if z is greater than or equal to 2.326. Reject H0 if z is less than or equal to –2.576. Reject H0 if z is greater than or equal to 2.5760
A researcher suspects the mean trough (the lowest dosage of medication required to see clinical improvement of symptoms) level for a medication used to treat arthritis is higher than was previously reported in other studies. If previous studies found the mean trough level of the population to be 3.7 micrograms/mL, and the researcher conducts a study among 93 newly diagnosed arthritis patients and finds the mean trough to be 6.1 micrograms/mL with a standard deviation of 1.2 micrograms/mL, the researcher’s hypothesis, for a level of significance of 1%, should resemble which of the following sets of hypothesis? H0: µ = 3.7 micrograms/mL; H1: µ > 3.7 micrograms/mL; alpha= .01 H0: µ > 3.7 micrograms/mL; H1: µ = 3.7 micrograms/mL; alpha= .01 H0: µ = 3.7 micrograms/mL; H1: µ > 3.7 micrograms/mL; alpha= .99 H0: µ > 3.7 micrograms/mL; H1: µ = 3.7 micrograms/mL; alpha= .99
A researcher suspects the mean trough (the lowest dosage of medication required to see clinical improvement of symptoms) level for a medication used to treat arthritis is higher than was previously reported in other studies. If previous studies found the mean trough level of the population to be 3.7 micrograms/mL, and the researcher conducts a study among 93 newly diagnosed arthritis patients and finds the mean trough to be 6.1 micrograms/mL with a standard deviation of 1.2 micrograms/mL, the researcher’s hypothesis, for a level of significance of 1%, should resemble which of the following sets of hypothesis? H0: µ = 3.7 micrograms/mL; H1: µ > 3.7 micrograms/mL; alpha= .01 H0: µ > 3.7 micrograms/mL; H1: µ = 3.7 micrograms/mL; alpha= .01 H0: µ = 3.7 micrograms/mL; H1: µ > 3.7 micrograms/mL; alpha= .99 H0: µ > 3.7 micrograms/mL; H1: µ = 3.7 micrograms/mL; alpha= .99
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