The immediate post shock conditions in a flow of nitrogen N2 are at constant velocity, and have a temperature T. of 0.06. Find the maximum dissociation fraction (a) which would be possible from energy considerations alone (for N₂, = 113,000 K) 0.24 ○ 0.0 1.0 0.32
The immediate post shock conditions in a flow of nitrogen N2 are at constant velocity, and have a temperature T. of 0.06. Find the maximum dissociation fraction (a) which would be possible from energy considerations alone (for N₂, = 113,000 K) 0.24 ○ 0.0 1.0 0.32
Introduction to Chemical Engineering Thermodynamics
8th Edition
ISBN:9781259696527
Author:J.M. Smith Termodinamica en ingenieria quimica, Hendrick C Van Ness, Michael Abbott, Mark Swihart
Publisher:J.M. Smith Termodinamica en ingenieria quimica, Hendrick C Van Ness, Michael Abbott, Mark Swihart
Chapter1: Introduction
Section: Chapter Questions
Problem 1.1P
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what is the correct answer for both questions?

Transcribed Image Text:The immediate post shock conditions in a flow of nitrogen N₂ are at constant velocity, and have a temperature T of 0.06. Find the maximum
dissociation fraction (a) which would be possible from energy considerations alone (for N₂, Ⓒ = 113,000 K)
0.24
0.0
1.0
0.32
In the above question what will the density (in kg m-³) be at a point where the N₂ is 10% dissociated (ie. a = 0.1)? The pressure behind the
shock is 100 kPa and the enthalpy of dissociation (D) is 33.6 MJ/kg.
0.0351
0.0792
0.12
0.0617
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