The mean income per person in the United States is $37,000, and the distribution of incomes follows a normal distribution. A random sample of 11 residents of Wilmington, Delaware, had a mean of $43,000 with a standard deviation of $8,800. At the .025 level of significance, is there enough evidence to conclude the residents of Wilmington, Delaware, have more income than the national average?Is there enough evidence to substantiate the residents of Wilmington, Delaware, have more income than the national average at .025 significance level?H₀: There is [blank] evidence to conclude that the mean income in Wilmington is [blank] $37,000.

The hypotheses are given below: Null hypothesis: H0:µ=37,000 Alternative hypothesis: H1:µ>37,000…

The Ihe meen incame per persen in the cnited Stetes Is 37,000, ondthe dstibution oF incomes follows Ĉ narmel distribution A residents af Wilminsten, Dekusre, had a meen a 43,000 with estrdorel devietion of 8,800. At the .025 level af evidence to conclude the resicents af Wilminsten Delewere, hove more income then the nehionel everese rondem semple af II Sicnihcence, is the enoush

The Ihe meen incame per persen in the cnited Stetes Is 37,000, ondthe dstibution oF incomes follows Ĉ narmel distribution A residents af Wilminsten, Dekusre, had a meen a 43,000 with estrdorel devietion of 8,800. At the .025 level af evidence to conclude the resicents af Wilminsten Delewere, hove more income then the nehionel everese rondem semple af II Sicnihcence, is the enoush

MATLAB: An Introduction with Applications

6th Edition

ISBN:9781119256830

Author:Amos Gilat

Publisher:Amos Gilat

Chapter1: Starting With Matlab

Section: Chapter Questions

Problem 1P

See similar textbooks

Similar questions

The following data (excluded outlier) is collected from a student's (David) exam score. Assume that distribution is normally distributed. David's exam score: 71 a) Analyze David's exam score based on the above table. b) Assume that distribution is bell-shaped, find the percentage who scored greater than David. Analyze his exam score based on the percentage you found.
4. In the ordered data: 20, a, 25, 30, 40, b, 49. If the first quartile=23.5 and IQR=19, then the values of a and b are: a=21.5, b=45.5 a=21, b=48 a=22, b=45 a=22.5 , b=45.5 5. Let X-Bin (12, 0.2), then * P (X 2 1) = O 1- 0.212 O 0.812 O1- 0.812 O 0.212
7.88 Aluminum cans contaminated by fire. A gigantic NW warehouse located in Tampa, Florida, stores approxi- mately 60 million empty aluminum beer and soda cans. Recently, a fire occurred at the warehouse. The smoke from the fire contaminated many of the cans with black- spot, rendering them unusable. A University of South Florida statistician was hired by the insurance com- pany to estimate p, the true proportion of cans in the warehouse that were contaminated by the fire. How many aluminum cans should be randomly sampled to estimate the true proportion to within .02 with 90% confidence?
1. Give an examle of a paired date set 2. Why is the chi-square distribution always positive?
1. The weight of packages that are sent by a certain parcel delivery service has a normal distribution with a mean of 12 pounds and a standard deviation of 3.5 pounds. The administration wants to establish a weight c beyond which there will be a premium. This value c will correspond to the one that groups the lower 99% of the parcel, therefore, this value is: a) 21.03 b) 3.85 c) 2.98 d) 20.14 2. The height of Colombian men is 170cm with a standard deviation of 3cm. In a random sample of 4 Colombian men, the probability that two of them are taller than 180cm is: a) 0.9982 b) 0.9995 c) 1.1036E-6 d) 4.2906E-4
The lengths of adult males' hands are normally distributed with mean 190 mm and standard deviation is 7.4 mm. Suppose that 44 individuals are randomly chosen. Round all answers to 4 where possible. a. What is the distribution of ? I - N( b. For the group of 44, find the probability that the average hand length is more than 189. c. Find the first quartile for the average adult male hand length for this sample size. d. For part b), is the assumption that the distribution is normal necessary? No Yes Submit Ouortion
Please strictly provide explanation for item 13 and 15
The General Social Survey asks questions about one’s happiness in marriage. Is there an association between gender and happiness in marriage? Use the data in the table to determine if gender is associated with happiness in marriage. Treat gender as the explanatory variable. Female Male Very happy 7,609 7,942 Pretty happy 3,738 4,47 Not too happy 259 460 a) Construct a frequency marginal distribution b) What percentage of males feel not too happy? c) Is gender associated with or independent from happiness in marriage? Why
O SPS Programs 5 n Uhllne LBCker. Vitu E Unuied document . G RII- GOogle search spanish In this problem, assume that the distribution of differences is approximately normal. Note: For degrees of freedom d.f. not in the Student's t table, use the closest d.f. that is smaller. In some situations, this cholce of d.f. may Increase the Pvalue by a small amount and therefore produce a slightly more "conservative" answer. At five weather stations on Trail Ridge Road in Rocky Mountain National Park, the peak wind gusts (in miles per hour) for January and Aprl are recorded below Weather Station 1 2 3 4 S 139 124 104 January 64 78 April 88 61 102 Does this Information Indicate that the peak wind gusts are higher in January than in April? Use a = 0.01. (Let d= January- April.) (a) what is the level of significance? State the null and alternate hypotheses. will you use a left-taled, noht-tailed, or two-talled test? O H H- 0, H H 0; nght-taled O Ho: He- 0; H, H-0; two-tafled O Hg: Ha> 0; H, Ha- 0;…
1. A group of 500 volunteers recorded an average age of 21.5 years and standard deviation of 9.6 years. Assumed the distribution is normally distributed. d) If 2.5% of the volunteers are older than Shirley how old is she? e) Between what ages is the middle 40% of the volunteers?
4. Jim wishes to estimate the average number of days students are absent from his STA 205 in a semester. In a random sample of 36 of her STA 205 students the mean number of absences was 2.853 days with a standard deviation of 1.878 days. Find the interval that is three standard deviations from the mean. Interpret this interval using either the Empirical Rule or Chebyshev's Rule (whichever is most appropriate for this distribution). Estimate the mean number of days students are absent from Jim's STA 205 using 90% confidence. Two-tail probability One-tail probability 0.20 0.10 0.05 0.02 0.01 0.10 0.05 0.025 0.01 0.005 Table T df df 30 1.310 1.697 2.042 2.457 2.750 30 32 1.309 1.694 2.037 2.449 2.738 32 35 1.306 1.690 2.030 2.438 2.725 35 1.684 2.021 2.423 2.704 2.690 40 1.303 40 45 1.301 1.679 2.014 2.412 45
The chromium percentages of the samples obtained from the drillings in the field are given below. Prepare the frequency table of the distribution by taking the lower limit of the first class as 20 and the class interval as 10 in the frequency table and answer the questions below a) What is the avarege of the distribution? b) What is the Standard Deviation of the Distribution? c) What is the coefficient of variation of the distribution? d) What is the median value of the distribution?