The mean income per person in the United States is $37,000, and the distribution of incomes follows a normal distribution. A random sample of 11 residents of Wilmington, Delaware, had a mean of $43,000 with a standard deviation of $8,800. At the .025 level of significance, is there enough evidence to conclude the residents of Wilmington, Delaware, have more income than the national average?Is there enough evidence to substantiate the residents of Wilmington, Delaware, have more income than the national average at .025 significance level?H₀: There is [blank] evidence to conclude that the mean income in Wilmington is [blank] $37,000.

The hypotheses are given below: Null hypothesis: H0:µ=37,000 Alternative hypothesis: H1:µ>37,000…

The Ihe meen incame per persen in the cnited Stetes Is 37,000, ondthe dstibution oF incomes follows Ĉ narmel distribution A residents af Wilminsten, Dekusre, had a meen a 43,000 with estrdorel devietion of 8,800. At the .025 level af evidence to conclude the resicents af Wilminsten Delewere, hove more income then the nehionel everese rondem semple af II Sicnihcence, is the enoush

The Ihe meen incame per persen in the cnited Stetes Is 37,000, ondthe dstibution oF incomes follows Ĉ narmel distribution A residents af Wilminsten, Dekusre, had a meen a 43,000 with estrdorel devietion of 8,800. At the .025 level af evidence to conclude the resicents af Wilminsten Delewere, hove more income then the nehionel everese rondem semple af II Sicnihcence, is the enoush

MATLAB: An Introduction with Applications

6th Edition

ISBN:9781119256830

Author:Amos Gilat

Publisher:Amos Gilat

Chapter1: Starting With Matlab

Section: Chapter Questions

Problem 1P

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