The ice cubes absorb 90,300 J of energy from the tea as it cools from 40 °C to 0 °C. What mass of tea is cooled, assuming the tea is mostly water? Ctea - 75.4 J/mol. K mass of tea = [?] g Hint: Pay attention to the units. mass, tea (g) Enter
Thermochemistry
Thermochemistry can be considered as a branch of thermodynamics that deals with the connections between warmth, work, and various types of energy, formed because of different synthetic and actual cycles. Thermochemistry describes the energy changes that occur as a result of reactions or chemical changes in a substance.
Exergonic Reaction
The term exergonic is derived from the Greek word in which ‘ergon’ means work and exergonic means ‘work outside’. Exergonic reactions releases work energy. Exergonic reactions are different from exothermic reactions, the one that releases only heat energy during the course of the reaction. So, exothermic reaction is one type of exergonic reaction. Exergonic reaction releases work energy in different forms like heat, light or sound. For example, a glow stick releases light making that an exergonic reaction and not an exothermic reaction since no heat is released. Even endothermic reactions at very high temperature are exergonic.
![**Thermal Energy Transfer and Mass Calculation**
**Problem Statement:**
The ice cubes absorb 90,300 J of energy from the tea as it cools from 40 °C to 0 °C. What mass of tea is cooled, assuming the tea is mostly water?
**Given Data:**
- Heat absorbed by ice cubes: \( 90,300 \text{ J} \)
- Initial temperature of tea: \( 40 \text{ °C} \)
- Final temperature of tea: \( 0 \text{ °C} \)
- Specific heat capacity of tea (\( c_{\text{tea}} \)): \( 75.4 \text{ J/mol·K} \)
**Formula to Use:**
The relation between heat energy (\( q \)), mass (\( m \)), specific heat capacity (\( c \)), and temperature change (\( \Delta T \)) is given by:
\[ q = mc\Delta T \]
Where:
- \( q \) is the heat energy (in joules, J)
- \( m \) is the mass (in grams, g)
- \( c \) is the specific heat capacity (in \( \text{J/mol·K} \))
- \( \Delta T \) is the change in temperature (in kelvin, K or degrees Celsius, °C)
Note that \( \Delta T \) in this context is \( 40 \text{ °C} - 0 \text{ °C} = 40 \text{ °C} \).
**Objective:**
Find the mass of tea (\( m \)) in grams.
**Hint:**
Pay attention to the units throughout the calculation to ensure consistency and accuracy.
**Input Box:**
`mass, tea (g)`
[Input Field] [Enter]](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2Fc32de472-a4f2-48c4-9a30-9bd31a36a4ce%2F32c2166c-b684-47d9-bc79-411d9a419f0d%2F7faf75_processed.jpeg&w=3840&q=75)
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