If 5750 joules of energy are added to 455 grams of granite at 24.00 °C, what is the final temperature of the granite? Cs granite is 0.79 J/g °C.
If 5750 joules of energy are added to 455 grams of granite at 24.00 °C, what is the final temperature of the granite? Cs granite is 0.79 J/g °C.
Chemistry
10th Edition
ISBN:9781305957404
Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Publisher:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Chapter1: Chemical Foundations
Section: Chapter Questions
Problem 1RQ: Define and explain the differences between the following terms. a. law and theory b. theory and...
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![**Problem 5: Temperature Change in Granite**
Given:
- Energy added: 5750 joules
- Mass of granite: 455 grams
- Initial temperature of granite: 24.00 °C
- Specific heat capacity of granite, \( C_s \): 0.79 J/g°C
**Question:**
What is the final temperature of the granite after adding the energy?
**Solution Approach:**
This problem requires using the formula for calculating the change in temperature when heat is added:
\[
q = m \cdot C_s \cdot \Delta T
\]
Where:
- \( q \) is the amount of heat added (5750 J),
- \( m \) is the mass (455 g),
- \( C_s \) is the specific heat capacity (0.79 J/g°C), and
- \( \Delta T \) is the change in temperature (final temperature - initial temperature).
Rearrange the formula to solve for the final temperature:
\[
\Delta T = \frac{q}{m \cdot C_s}
\]
Calculate \( \Delta T \) and then find the final temperature by adding the initial temperature to \( \Delta T \).](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2F805df41e-b889-4c16-a267-318b4eb3cf21%2F8497f2cc-0170-4d96-8daf-c2e0b2c28498%2Fwvgsrmi_processed.png&w=3840&q=75)
Transcribed Image Text:**Problem 5: Temperature Change in Granite**
Given:
- Energy added: 5750 joules
- Mass of granite: 455 grams
- Initial temperature of granite: 24.00 °C
- Specific heat capacity of granite, \( C_s \): 0.79 J/g°C
**Question:**
What is the final temperature of the granite after adding the energy?
**Solution Approach:**
This problem requires using the formula for calculating the change in temperature when heat is added:
\[
q = m \cdot C_s \cdot \Delta T
\]
Where:
- \( q \) is the amount of heat added (5750 J),
- \( m \) is the mass (455 g),
- \( C_s \) is the specific heat capacity (0.79 J/g°C), and
- \( \Delta T \) is the change in temperature (final temperature - initial temperature).
Rearrange the formula to solve for the final temperature:
\[
\Delta T = \frac{q}{m \cdot C_s}
\]
Calculate \( \Delta T \) and then find the final temperature by adding the initial temperature to \( \Delta T \).
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