If 5750 joules of energy are added to 455 grams of granite at 24.00 °C, what is the final temperature of the granite? Cs granite is 0.79 J/g °C.

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ISBN:9781305957404
Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Publisher:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Chapter1: Chemical Foundations
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**Problem 5: Temperature Change in Granite**

Given:  
- Energy added: 5750 joules  
- Mass of granite: 455 grams  
- Initial temperature of granite: 24.00 °C  
- Specific heat capacity of granite, \( C_s \): 0.79 J/g°C  

**Question:**  
What is the final temperature of the granite after adding the energy?

**Solution Approach:**

This problem requires using the formula for calculating the change in temperature when heat is added:

\[
q = m \cdot C_s \cdot \Delta T
\]

Where: 
- \( q \) is the amount of heat added (5750 J),
- \( m \) is the mass (455 g),
- \( C_s \) is the specific heat capacity (0.79 J/g°C), and
- \( \Delta T \) is the change in temperature (final temperature - initial temperature).

Rearrange the formula to solve for the final temperature:

\[
\Delta T = \frac{q}{m \cdot C_s}
\]

Calculate \( \Delta T \) and then find the final temperature by adding the initial temperature to \( \Delta T \).
Transcribed Image Text:**Problem 5: Temperature Change in Granite** Given: - Energy added: 5750 joules - Mass of granite: 455 grams - Initial temperature of granite: 24.00 °C - Specific heat capacity of granite, \( C_s \): 0.79 J/g°C **Question:** What is the final temperature of the granite after adding the energy? **Solution Approach:** This problem requires using the formula for calculating the change in temperature when heat is added: \[ q = m \cdot C_s \cdot \Delta T \] Where: - \( q \) is the amount of heat added (5750 J), - \( m \) is the mass (455 g), - \( C_s \) is the specific heat capacity (0.79 J/g°C), and - \( \Delta T \) is the change in temperature (final temperature - initial temperature). Rearrange the formula to solve for the final temperature: \[ \Delta T = \frac{q}{m \cdot C_s} \] Calculate \( \Delta T \) and then find the final temperature by adding the initial temperature to \( \Delta T \).
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