1. The metabolism of one mole of glycerol trioleate, C5 H93O6, a common fat, produces 3.022 x 10*kJ of heat. How many grams of the fat must be burned to raise the temperature of 50 g of water from 25.0°C to 30.0°C?

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**Problem: Metabolism of Glycerol Trioleate**

The metabolism of one mole of glycerol trioleate, \( \text{C}_{51}\text{H}_{93}\text{O}_{6} \), a common fat, produces \( 3.022 \times 10^4 \, \text{kJ} \) of heat. How many grams of the fat must be burned to raise the temperature of 50 g of water from 25.0°C to 30.0°C?

---

This problem involves calculating the amount of fatty substance required to provide enough energy to raise a specific amount of water by 5°C. This involves using the heat capacity formula to determine the energy needed for the temperature change and then use the metabolic energy of the fat to find out the mass required.

**The Key Concepts:**

1. **Heat Capacity of Water:**
   - For water, the specific heat capacity (\( c \)) is \( 4.18 \, \text{J/g}^\circ\text{C} \).

2. **Energy Calculation:**
   - The amount of energy (\( Q \)) required to raise the temperature can be calculated with:
     \[ Q = mc\Delta T \]
     where \( m \) is the mass of the water, \( c \) is its specific heat capacity, and \( \Delta T \) is the temperature change.

3. **Metabolic Energy of Glycerol Trioleate:**
   - The metabolism of one mole of this fat releases \( 3.022 \times 10^4 \, \text{kJ} \), which can be converted to Joules if necessary (1 kJ = 1000 J).

**Solution Steps:**

1. Calculate \( Q \) using the formula for the 50 g water temperature increase.
2. Determine how much fat is required using the energy released per mole of glycerol trioleate.

This analysis can help understand thermodynamics and energy transfer in biological systems.
Transcribed Image Text:**Problem: Metabolism of Glycerol Trioleate** The metabolism of one mole of glycerol trioleate, \( \text{C}_{51}\text{H}_{93}\text{O}_{6} \), a common fat, produces \( 3.022 \times 10^4 \, \text{kJ} \) of heat. How many grams of the fat must be burned to raise the temperature of 50 g of water from 25.0°C to 30.0°C? --- This problem involves calculating the amount of fatty substance required to provide enough energy to raise a specific amount of water by 5°C. This involves using the heat capacity formula to determine the energy needed for the temperature change and then use the metabolic energy of the fat to find out the mass required. **The Key Concepts:** 1. **Heat Capacity of Water:** - For water, the specific heat capacity (\( c \)) is \( 4.18 \, \text{J/g}^\circ\text{C} \). 2. **Energy Calculation:** - The amount of energy (\( Q \)) required to raise the temperature can be calculated with: \[ Q = mc\Delta T \] where \( m \) is the mass of the water, \( c \) is its specific heat capacity, and \( \Delta T \) is the temperature change. 3. **Metabolic Energy of Glycerol Trioleate:** - The metabolism of one mole of this fat releases \( 3.022 \times 10^4 \, \text{kJ} \), which can be converted to Joules if necessary (1 kJ = 1000 J). **Solution Steps:** 1. Calculate \( Q \) using the formula for the 50 g water temperature increase. 2. Determine how much fat is required using the energy released per mole of glycerol trioleate. This analysis can help understand thermodynamics and energy transfer in biological systems.
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