The hydrogenation of pyridine to piperidine C;H;N(g) + 3 H2(g) 2 C;H,N(g) is an équilibrium pročess whose équilibrium constant is given by the equation 10.560 K log10 K = -20.281 + T (a) Calculate the value of K at T = 500 K. (b) If the partial pressure of hydrogen is 1.00 atm, what fraction of the nitrogen is in the form of pyridine mol- ecules at T = 500 K?
The hydrogenation of pyridine to piperidine C;H;N(g) + 3 H2(g) 2 C;H,N(g) is an équilibrium pročess whose équilibrium constant is given by the equation 10.560 K log10 K = -20.281 + T (a) Calculate the value of K at T = 500 K. (b) If the partial pressure of hydrogen is 1.00 atm, what fraction of the nitrogen is in the form of pyridine mol- ecules at T = 500 K?
Chemistry
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Chapter1: Chemical Foundations
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
Transcribed Image Text:The hydrogenation of pyridine to piperidine
C;H;N(g) + 3 H2(g) 2 C;H,N(g)
is an équilibrium pročess whose équilibrium constant is
given by the equation
10.560 K
log10 K = -20.281 +
T
(a) Calculate the value of K at T = 500 K.
(b) If the partial pressure of hydrogen is 1.00 atm, what
fraction of the nitrogen is in the form of pyridine mol-
ecules at T = 500 K?
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