The hydrogen molecule comes apart (dissociates) when it is excited internally by 4.5 eV. If this molecule behaves exactly like a harmonic oscillator with classical frequency f=8.277-10¹4 rad/s, find the vibrational quantum number corresponding to its 4.5-ev dissociation energy. Constants: h= 6.626-10-34 [J-s], ħ=h/2π, and w=f. 21.
The hydrogen molecule comes apart (dissociates) when it is excited internally by 4.5 eV. If this molecule behaves exactly like a harmonic oscillator with classical frequency f=8.277-10¹4 rad/s, find the vibrational quantum number corresponding to its 4.5-ev dissociation energy. Constants: h= 6.626-10-34 [J-s], ħ=h/2π, and w=f. 21.
Related questions
Question
![The hydrogen molecule comes apart (dissociates) when it is excited internally by 4.5
eV. If this molecule behaves exactly like a harmonic oscillator with classical frequency
f=8.277-10¹4 rad/s, find the vibrational quantum number corresponding to its 4.5-eV
dissociation energy. Constants: h = 6.626-10-34 [J-s], ħ=h/2π, and w=f. 2π.](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2F92572cf8-ed26-4227-b4ce-32944a8c203e%2F06b186d5-2c5f-421a-863a-cc02f2bc5a4b%2Ful6iij_processed.jpeg&w=3840&q=75)
Transcribed Image Text:The hydrogen molecule comes apart (dissociates) when it is excited internally by 4.5
eV. If this molecule behaves exactly like a harmonic oscillator with classical frequency
f=8.277-10¹4 rad/s, find the vibrational quantum number corresponding to its 4.5-eV
dissociation energy. Constants: h = 6.626-10-34 [J-s], ħ=h/2π, and w=f. 2π.
Expert Solution
This question has been solved!
Explore an expertly crafted, step-by-step solution for a thorough understanding of key concepts.
Step by step
Solved in 2 steps
