The hydrogen atom is described by the Schrodinger equation, with a solution nım(r,&,0) = Rn1(r)Ym (0,0) 1/2 |m| h² ·√²y + V¥ = Eч. 2m where Y™ (0, 4) = (-1) ((2+1)(l|m|)!) plm (cos 0)eimo, with the first few 4π(1+|m|)! - Legendre polynomials: Po (cos 0) = 1, Pº (cos 0) = cos 0, P₂ (cos 0) = ½ (3 cos 0² − 1). j=0 l−1 Given V (r) -e2 Απεργ ero , Rnı(r) = ±²± p²+¹e¯³ Σn=l¯¹ C¡ p³ where p r = with nao Απεργ do = -being the Bohr radius, and j+1 2 = where Co = for n=1, cj me2 2(j+1+1)-2n (j+1)(j+21+2) write down 100 and show it is a solution to the Schrodinger equation

The hydrogen atom is described by the Schrodinger equation, with a solution nım(r,&,0) = Rn1(r)Ym (0,0) 1/2 |m| h² ·√²y + V¥ = Eч. 2m where Y™ (0, 4) = (-1) ((2+1)(l|m|)!) plm (cos 0)eimo, with the first few 4π(1+|m|)! - Legendre polynomials: Po (cos 0) = 1, Pº (cos 0) = cos 0, P₂ (cos 0) = ½ (3 cos 0² − 1). j=0 l−1 Given V (r) -e2 Απεργ ero , Rnı(r) = ±²± p²+¹e¯³ Σn=l¯¹ C¡ p³ where p r = with nao Απεργ do = -being the Bohr radius, and j+1 2 = where Co = for n=1, cj me2 2(j+1+1)-2n (j+1)(j+21+2) write down 100 and show it is a solution to the Schrodinger equation