A weak acid HX partially hydrolyzes in water causing the pH to change. Take the acid dissociation constant of HX to be K, and its initial concentration in solution to be Co- If the "small-x" approximation cannot be used in this case, then which quadratic equation allows to solve for x correctly? x² + K, Cox - K„Co = 0 x²+ KaCox + K₁Co = 0 x²+ Kx K₁Co = 0 x²+ Kx + KC₁ = 0

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A weak acid HX partially hydrolyzes in water causing the pH to change.
Take the acid dissociation constant of HX to be K, and its initial
concentration in solution to be Co-
If the "small-x" approximation cannot be used in this case, then which
quadratic equation allows to solve for x correctly?
x² + K, Cox - K„Co = 0
x²+ KaCox + K₁Co = 0
x²+ Kx K₁Co = 0
x²+ Kx + KC₁ = 0
Transcribed Image Text:A weak acid HX partially hydrolyzes in water causing the pH to change. Take the acid dissociation constant of HX to be K, and its initial concentration in solution to be Co- If the "small-x" approximation cannot be used in this case, then which quadratic equation allows to solve for x correctly? x² + K, Cox - K„Co = 0 x²+ KaCox + K₁Co = 0 x²+ Kx K₁Co = 0 x²+ Kx + KC₁ = 0
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