The hotation from this problem is from Understanding Cryptography by Paar and Pelzi. Ne conduct a known-plaintext attack against an LFSR. Through trial and error we have determined that the number of states is m = 4. The plaintext given by 00010110 = XoX X2XX4X5 X6X

Elements Of Electromagnetics
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otINote: The notation from this problem is from Understanding Cryptography by Paar and Pelzl.
We conduct a known-plaintext attack against an LFSR. Through trial and error we have determined that the number of states is m = 4.
The plaintext given by
when encrypted by the LFSR produced the ciphertext
01011000 = yo yı y2 ys Yo Y
%3D
What are the tap bits of the LFSR? Please enter your answer as unspaced binary digits (e.g. 0101 to represent py = 0, P = 1, P = 0, Po= 1).
Transcribed Image Text:otINote: The notation from this problem is from Understanding Cryptography by Paar and Pelzl. We conduct a known-plaintext attack against an LFSR. Through trial and error we have determined that the number of states is m = 4. The plaintext given by when encrypted by the LFSR produced the ciphertext 01011000 = yo yı y2 ys Yo Y %3D What are the tap bits of the LFSR? Please enter your answer as unspaced binary digits (e.g. 0101 to represent py = 0, P = 1, P = 0, Po= 1).
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