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Example: A room with dimensions 4m x 3 m ve 2,5 m are covered with following materials at 500 Hz with an absorption coefficients are 0.02 (floor), 0.15 (ceiling) and 0.05 (walls). Determine a) the room constant and reverberation time, and b) the required covering area for reducing the reverberation time to 0.8 s by applying an acoustic material with absorption coeefficient of 0.2.

Example: A room with dimensions 4m x 3 m ve 2,5 m are covered with following materials at 500 Hz with an absorption coefficients are 0.02 (floor), 0.15 (ceiling) and 0.05 (walls). Determine a) the room constant and reverberation time, and b) the required covering area for reducing the reverberation time to 0.8 s by applying an acoustic material with absorption coeefficient of 0.2.

Elements Of Electromagnetics
Elements Of Electromagnetics
7th Edition
ISBN:9780190698614
Author:Sadiku, Matthew N. O.
Publisher:Sadiku, Matthew N. O.
ChapterMA: Math Assessment
Section: Chapter Questions
Problem 1.1MA
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Example: A room with dimensions 4m x 3 m ve 2,5 m are covered with following materials at 500 Hz with an absorption coefficients are 0.02 (floor), 0.15 (ceiling) and 0.05 (walls). Determine a) the room constant and reverberation time, and b) the required covering area for reducing the reverberation time to 0.8 s by applying an acoustic material with absorption coeefficient of 0.2.
Transcribed Image Text:Example: A room with dimensions 4m x 3 m ve 2,5 m are covered with following materials at 500 Hz with an absorption coefficients are 0.02 (floor), 0.15 (ceiling) and 0.05 (walls). Determine a) the room constant and reverberation time, and b) the required covering area for reducing the reverberation time to 0.8 s by applying an acoustic material with absorption coeefficient of 0.2.
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