The heights of adult men in America are normally distributed, with a mean of 69.8 inches and a standard deviation of 2.63 inches. The heights of adult women in America are also normally distributed, but with a mean of 64.5 inches and a standard deviation of 2.54 inches. a) If a man is 6 feet 3 inches tall, what is his z-score (to two decimal places)? Z = 1.98 b) What percentage of men are SHORTER than 6 feet 3 inches? Round to nearest tenth of a percent. 97.6 c) If a woman is 5 feet 11 inches tall, what is her z-score (to two decimal places)? z = 2.56 d) What percentage of women are TALLER than 5 feet 11 inches? Round to nearest tenth of a percent.

MATLAB: An Introduction with Applications
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part d

**Understanding Z-Scores and Height Distribution**

In the study of statistics, understanding how data such as heights are distributed can be insightful. Here, we examine the normal distribution of heights for adult men and women in America.

- **Men:** Mean = 69.8 inches, Standard Deviation = 2.63 inches
- **Women:** Mean = 64.5 inches, Standard Deviation = 2.54 inches

### Questions:

**a) If a man is 6 feet 3 inches tall, what is his z-score (rounded to two decimal places)?**

   - **Calculation:**  
     \[ z = \frac{{\text{{Height in inches}} - \text{{Mean}}}}{\text{{Standard Deviation}}} \]
   - **Result:**  
     \[ z = 1.98 \]

**b) What percentage of men are shorter than 6 feet 3 inches? (Rounded to the nearest tenth of a percent.)**

   - **Result:**  
     \[ 97.6\% \]

**c) If a woman is 5 feet 11 inches tall, what is her z-score (rounded to two decimal places)?**

   - **Calculation:**  
     \[ z = \frac{{\text{{Height in inches}} - \text{{Mean}}}}{\text{{Standard Deviation}}} \]
   - **Result:**  
     \[ z = 2.56 \]

**d) What percentage of women are taller than 5 feet 11 inches? (Round to the nearest tenth of a percent.)**

   - **Instruction:**  
     This requires calculating the percentage of women that fall above a certain z-score.

By understanding these calculations, we gain insights into how individual heights compare to the average and the population as a whole.
Transcribed Image Text:**Understanding Z-Scores and Height Distribution** In the study of statistics, understanding how data such as heights are distributed can be insightful. Here, we examine the normal distribution of heights for adult men and women in America. - **Men:** Mean = 69.8 inches, Standard Deviation = 2.63 inches - **Women:** Mean = 64.5 inches, Standard Deviation = 2.54 inches ### Questions: **a) If a man is 6 feet 3 inches tall, what is his z-score (rounded to two decimal places)?** - **Calculation:** \[ z = \frac{{\text{{Height in inches}} - \text{{Mean}}}}{\text{{Standard Deviation}}} \] - **Result:** \[ z = 1.98 \] **b) What percentage of men are shorter than 6 feet 3 inches? (Rounded to the nearest tenth of a percent.)** - **Result:** \[ 97.6\% \] **c) If a woman is 5 feet 11 inches tall, what is her z-score (rounded to two decimal places)?** - **Calculation:** \[ z = \frac{{\text{{Height in inches}} - \text{{Mean}}}}{\text{{Standard Deviation}}} \] - **Result:** \[ z = 2.56 \] **d) What percentage of women are taller than 5 feet 11 inches? (Round to the nearest tenth of a percent.)** - **Instruction:** This requires calculating the percentage of women that fall above a certain z-score. By understanding these calculations, we gain insights into how individual heights compare to the average and the population as a whole.
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