The heights of adult men in America are normally distributed, with a mean of 69.1 inches and astandard deviation of 2.66 inches. The heights of adult women in America are also normallydistributed, but with a mean of 64.7 inches and a standard deviation of 2.59 inches.a) If a man is 6 feet 3 inches tall, what is his z-score (to two decimal places)?b) If a woman is 5 feet 11 inches tall, what is her z-score (to two decimal places)?c) Who is relatively taller?O The 5 foot 11 inch Amnerican womanO The 6 foot 3 inch American manSubmit QuestionType here to search

GivenFor heights of adult menMean(μ)=69.1 inchesstandard deviation(σ)=2.66 inchesFor heights of…

Answered: The heights of adult men in America are…

MATLAB: An Introduction with Applications

6th Edition

ISBN:9781119256830

Author:Amos Gilat

Publisher:Amos Gilat

Chapter1: Starting With Matlab

Section: Chapter Questions

Problem 1P

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The Acme Company manufactures widgets. The distribution of widget weights is bell-shaped. The widget weights have a mean of 65 ounces and a standard deviation of 3 ounces. Use the Empirical Rule. Suggestion: sketch the distribution in order to answer these questions. a) 99.7% of the widget weights lie between and b) What percentage of the widget weights lie between 59 and 74 ounces? c) What percentage of the widget weights lie below 68 ? %
The heights of Crepe Myrtle saplings at a local nursery are measured and the data recorded. The data is then plotted and the distribution is found to be bell-shaped. The mean of the set is 67 inches and the standard deviation is 3 inches. A graph of the situation is shown below: 58 61 64 67 70 73 76 a) What percentage of the saplings is more than 70 inches tall? b) What percentage of the saplings is between 61 and 73 inches tall?
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The Acme Company manufactures widgets. The distribution of widget weights is bell-shaped. The widget weights have a mean of 39 ounces and a standard deviation of 10 ounces. Use the Empirical Rule. Suggestion: sketch the distribution in order to answer these questions. a) 99.7% of the widget weights lie between and b) What percentage of the widget weights lie between 29 and 69 ounces? c) What percentage of the widget weights lie below 59 ?
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The distribution of heights of adult American men is approximately normal with a mean of 69 inches and a standard deviation of 2.5 inches. a. What percent of these men are at least 71.5 inches tall? b. What percent of these men are between 64 and 74 inches tall?
Use z scores to compare the given values. The tallest living man at one time had a height of 238 cm. The shortest living man at that time had a height of 142.4 cm. Heights of men at that time had a mean of 175.45 cm and a standard deviation of 5.59 cm. Which of these two men had the height that was more extreme? ... Since the z score for the tallest man is z = 0 and the z score for the shortest man is z = the man had the height that was Im- more extreme. (Round to two decimal places.) shortest tallest
Please answer the following three multiple choice questions :) Summarized below are data for a study to see if hours of sleep per day for med and non-med students are the same: n x¯ s med students 25 5.8 0.83 non-med students 32 6.3 1.39 1. Find the test statistic (assume unequal standard deviation) A. -15.44 B. -5.69 C. -1.69 D. -1.81 2. Let tstat represent the value of the test statistic from the previous question. The degrees of freedom for the test are df = 52. To test the claim that the mean hours of sleep for med and non-med students is different, the P-value is calculated as: A. 2*pt( tstat, df=52, lower.tail = TRUE) B. 2*pt( tstat, df=52, lower.tail = FALSE) C. pt( tstat, df=52, lower.tail = TRUE) D. pt( tstat, df=52, lower.tail = FALSE) 3. The correct P-value is 0.098. At α = 0.05, we A. reject H0. The claim that means are different is not supported. B. reject H0. The claim that means are different is supported. C. fail to reject…
The Acme Company manufactures widgets. The distribution of widget weights is bell-shaped. The widget weights have a mean of 63 ounces and a standard deviation of 7 ounces. a) 99.7% of the widget weights lie between and b) What percentage of the widget weights lie between 56 and 84 ounces? c) What percentage of the widget weights lie above 49 ? %
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