The half-wave rectifier in Figure 2–19 has a 250-μF filter capacitor and a 1.5-kOhm load. The ac source is 120 V rms with frequency 60 Hz. The voltage drop across the silicon diode is 0.7V. Assuming light loading, find(a) the dc value of the load voltage;(b) the peak-to-peak value of the ripple(c) the %-ripple(d) plot vin(t), vR(t) (output without the filter cap) and vL(t) (output with the filter cap) all on the same graph FIGURE 2-19 When loadvc(t) = vL(t)resistance R, is connectedacross the filter capacitor,the capacitor charges anddischarges, creating a loadvoltage that has a ripplevoltage superimposed ona dc level.v(t)ripple voltageVPRVpp VdcVprwaveform withfilter capacitordisconnectedwaveform with filtercapacitor and loadresistance connected´discharge(load)chargingload resistancecurrent,when inputpulses arecurrent,Ewhen inputpulses aree;RLpresentabsent

Answered: The half-wave rectifier in Figure 2–19…

Introductory Circuit Analysis (13th Edition)

13th Edition

ISBN:9780133923605

Author:Robert L. Boylestad

Publisher:Robert L. Boylestad

Chapter1: Introduction

Section: Chapter Questions

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Question

The half-wave rectifier in Figure 2–19 has a 250-μF filter capacitor and a 1.5-kOhm load. The ac source is 120 V rms with frequency 60 Hz. The voltage drop across the silicon diode is 0.7V. Assuming light loading, find

(a) the dc value of the load voltage;

(b) the peak-to-peak value of the ripple

(c) the %-ripple

(d) plot vin(t), v_R(t) (output without the filter cap) and v_L(t) (output with the filter cap) all on the same graph

FIGURE 2-19 When load
vc(t) = vL(t)
resistance R, is connected
across the filter capacitor,
the capacitor charges and
discharges, creating a load
voltage that has a ripple
voltage superimposed on
a dc level.
v(t)
ripple voltage
VPR
Vpp Vdc
Vpr
waveform with
filter capacitor
disconnected
waveform with filter
capacitor and load
resistance connected
´discharge
(load)
charging
load resistance
current,
when input
pulses are
current,
Ewhen input
pulses are
e;
RL
present
absent

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