The half-life of krypton-91 (9Kr) is 10 s. At time t = 0 a heavy canister contains 4 g of this radioactive gas. (a) Find a function m(t) = mo2-t/h that models the amount of 91Kr remaining in the canister after t seconds. m(t) = 10 (b) Find a function m(t) = moe-rt that models the amount of 91Kr remaining in the canister after t seconds. (Round your r value to five decimal places.) m(t) = (c) How much 91Kr remains after 1 min? (Round your answer to three decimal places.) (d) After how long will the amount of 91Kr remaining be reduced to 1 ug (1 microgram, or 10-° g)? (Round your answer to the nearest whole number.) sec

Advanced Engineering Mathematics
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ISBN:9780470458365
Author:Erwin Kreyszig
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Chapter2: Second-order Linear Odes
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The half-life of krypton-91 (9Kr) is 10 s. At time t = 0 a heavy canister contains 4 g of this radioactive gas.
(a) Find a function m(t) = m,2-t/h that models the amount of 91Kr remaining in the canister after t seconds.
m(t) = 10
(b) Find a function m(t) = moe-rt that models the amount of 91Kr remaining in the canister after t seconds. (Round your r value to five decimal places.)
m(t) =
(c) How much 9'Kr remains after 1 min? (Round your answer to three decimal places.)
(d) After how long will the amount of 9'Kr remaining be reduced to 1 µg (1 microgram, or 10-° g)? (Round your answer to the nearest whole number.)
sec
Transcribed Image Text:The half-life of krypton-91 (9Kr) is 10 s. At time t = 0 a heavy canister contains 4 g of this radioactive gas. (a) Find a function m(t) = m,2-t/h that models the amount of 91Kr remaining in the canister after t seconds. m(t) = 10 (b) Find a function m(t) = moe-rt that models the amount of 91Kr remaining in the canister after t seconds. (Round your r value to five decimal places.) m(t) = (c) How much 9'Kr remains after 1 min? (Round your answer to three decimal places.) (d) After how long will the amount of 9'Kr remaining be reduced to 1 µg (1 microgram, or 10-° g)? (Round your answer to the nearest whole number.) sec
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