The half-life for the alpha decay of 226Ra to form 222Rn is 1.60×10 y. Suppose the energy of the alpha particle is 4.50 MeV and that 1.09 g of 226Ra, freed of any other radioactive materials, were placed in a calorimeter containing 11.3 g of water, initially at 21.5°C. Calculate the temperature the water would reach after 1.07 hour. Neglect the heat capacity of the calorimeter and heat loss to the surroundings. Take the specific heat of water to be 4.184 JK g1 and the mass of a 226Ra atom to be 226.025 u. (1 eV = 1.6022 x 1o 19 3)
The half-life for the alpha decay of 226Ra to form 222Rn is 1.60×10 y. Suppose the energy of the alpha particle is 4.50 MeV and that 1.09 g of 226Ra, freed of any other radioactive materials, were placed in a calorimeter containing 11.3 g of water, initially at 21.5°C. Calculate the temperature the water would reach after 1.07 hour. Neglect the heat capacity of the calorimeter and heat loss to the surroundings. Take the specific heat of water to be 4.184 JK g1 and the mass of a 226Ra atom to be 226.025 u. (1 eV = 1.6022 x 1o 19 3)
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![The half-life for the alpha decay of 226Ra to form 222Rn is 1.60×10³ y. Suppose the energy of
the alpha particle is 4.50 MeV and that 1.09 g of 226Ra, freed of any other radioactive
materials, were placed in a calorimeter containing 11.3 g of water, initially at 21.5°C. Calculate
the temperature the water would reach after 1.07 hour. Neglect the heat capacity of the
calorimeter and heat loss to the surroundings. Take the specific heat of water to be 4.184 JK
g1 and the mass of a 226Ra atom to be 226.025 u. (1 eV = 1.6022 x 1o 19 3)](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2F8f54eff6-5929-410b-a303-23270aa49ee9%2Fa48661c7-b073-4a14-87d3-78031f07e9d6%2Fxxqhehu_processed.jpeg&w=3840&q=75)
Transcribed Image Text:The half-life for the alpha decay of 226Ra to form 222Rn is 1.60×10³ y. Suppose the energy of
the alpha particle is 4.50 MeV and that 1.09 g of 226Ra, freed of any other radioactive
materials, were placed in a calorimeter containing 11.3 g of water, initially at 21.5°C. Calculate
the temperature the water would reach after 1.07 hour. Neglect the heat capacity of the
calorimeter and heat loss to the surroundings. Take the specific heat of water to be 4.184 JK
g1 and the mass of a 226Ra atom to be 226.025 u. (1 eV = 1.6022 x 1o 19 3)
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