The gusset shown in the figure is bolted to the column flange by 7-20mm A490M bolts in double shear. Determine the stress in the most heavily-loaded bolt (threads are not excluded on the shear plane). 140 KN 200 mm 175 mm Hint: Locate first the centroid of the group of bolts. Đ 150 mm 150 mm # 150 mm A 7-20 mm bolts ☺
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- Check the bolted section of the given gusset plate connection assuming that the connection is done by M12 bolts with a staggered arrangement. The maximum design tensile axial force to be sustained is Ned = 168 kN. Assume a grade of S235 steel. P. Gusset plate BỘ do=13mm Gusset plate O DO t=16mm t-16mm1 Ni.Ed FO NtEd do=13mm do3D13mm G. 40mm 40mm 140 mm 240mm 30mmThe bolted connection shown is a bearing type connection. Which of the following best gives the shearing capacity, ØRn. of the bolts? Consider threads excluded from shear plane and deformation at bolt hole is a design consideration. Standard size holes. PL350x12mm = 250 MPa C250x22.8 70 114 M20 A490 70 40' 60' 60 '40 SECT. A d tw bf tf Mm 15.8 mm^2 mm mm mm mm C250x22.8 2880 254 6.1 65 11.1 Ix(10^6) Sx(10^3) ly(10^6) Sy(10^3) Zx(10^3) Zy(10^3) rx ry mm^4 mm^3 mm mm^4 mm^3 mm mm^3 mm^3 27.7 218 98.1 0.912 18.5 18.5 257 40.3 O 424.8 KN O 1,102.7 KN O 3,770.7 KN O 1,637.1 KNProblem. A bolted connection shown consists of two plates 300 mm x 12 mm connected by 4 - 22 mm diameter bolts. 12 mm bolts t=12 mm t=12 mm P. P- P 300 75 75 75 Edge distances -75 mm dhole for tensile and rupture d, +3 mm dnole for bearing strength for L- de +1.5 mm Fy 248 MPa F.- 400 MPa
- Question 17 2L5x3x7mm tension momber is connocted to a gussot plate by 16-mm-diameter bolts as shown in the figure, Given that e= 30 mm, s= 50 mm, Fy =345 MPa and Fu=402 MPa, caicukato the following 2 L5 x3x % LLBD (two angles, long legs back-to-back) A242 stoel 60 mm e (am) (mn) e (mm) 55 Not area in shoar for a single angle under block shear lailue, Ariv mm? 56. Not area in tension for a single anglo under.block shoar failuto Arit = 57. Norninal block shear strongth in kN of the double angle Use Ups 10, Pn INPUT ALL ANSWERS AS WHOLE NUMBERDesign the bolted connectic n. When a bracket bolted to the flange of a column using a bracket plate as shown in fig. Using bracket plate. Using M20 bolts of grade 4.6 given ; column section= ISHB 450 Bracket plate thickness=11nm p=450KN E=330mm p=55mm bolt size=M20From the bolted connection shown, the diameter of bolts is 20 mm with the hole diameter equal to 3mm larger than the bolt diameter, the angular section is 100x75x8mm, with an area of 1340 mm^2. Thickness of gusset plate is 9 mm. the gusset plate. (a)If T = 200KN, compute the shearing stress on the bolts. (b)If the allowable shearing stress on the bolt is 145MPa, compute the value of T.
- Material Strengths: Fy = 248 MPa, F = 400 MPa For the two lines of bolt holes, the pitch is the value that will give a net area DEFG equal to the one along ABC. The diameter of the holes is 22 mm. The thickness of the plate is 12 mm. Determine the LRFD design tensile strength based on yielding on gross area. D A to 50 1 ÓB 50 50 ic O 410 kN O 464 kN O 446 kN O 401 KN F IG Pitch Pitch KISS|Y4. An UPE 300 is to be used as a tension member and it is bolted to a 10mm thick gusset plate with bearing type 8-M20 8.8 bolts as shown in the figure below. a. Check all spacing and edge distance requirements. b. Compute the allowable tensile strength of the channel UPE 300. Don't consider shear strength of the bolts and bearing strength of the bolt holes. [all dimensions are in mm] Material both for gusset plate and UPE 300: S275 F-275N/mm² Fu=430N/mm² UPE 300 Ag = 5660 mm² tw 9.5 mm x = 28.9 mm 70 160 70 + 10mm thick gusset plate +50+ 80 -80-80-50 o +50+80 -80 80-50 UPE 300Question 3 Determine the capacity of plate as well as below connection based on Balts (4) in the below Following reactions :- 7 11 A325, $4 þ Bolts use! Use: AISC manual U Moment = 10 kip-67 2 kip (2) Shear (3) Axial 2 kip رب Ź Plate (A 36) 10 " x 10" x ≤ 11 8 HSS. их их nxuxt 4 H² 7
- Problem 6: Assume that the pieces making up the connection are adequate, and very stiff such that prying forces can be disregarded, and that the nominal tensile stresses on the M20-F2280 bolts govern. The service load shown consists of 25% dead load and 75% live load. Use LRFD. 1 || T = 620 kN Calculate the factored load applied to the connection shown. Calculate the nominal tensile strength of one bolt. How many bolts are required to resist the load? I I I T = 620 kNThe connection shown is subjected to a tensile force of P = 100 kN. The allowable shear stress for the bolts is 100 MPa. Assume each bolt supports an equal portion of the load. Determine the required diameter of the bolts. a. 20.6 mm b. 25.2 mm c.35.7 mm d.17.8 mm choose letter of correct answerEXAMPLE #2: Compute the block shear design strength of the tension member shown in the figure. The holes are for 7/8- inch bolts and A36 steel is used (Fy 36 ksi, Fu = 58ksi) Assime Ubs* 10 L3½ x 3% x %, A36 3" 3" 76-in, bolts