The ground-state energy of a harmonic oscillator is 5.60 eV.
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The ground-state energy of a harmonic oscillator is 5.60 eV.

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- A quantum simple harmonic oscillator consists of an electron bound by a restoring force proportional to its position relative to a certain equilibrium point. The proportionality constant is 8.11 N/m. What is the longest wavelength of light that can excite the oscillator? ps:- answer is not 443.68Prove that, to three-digit accuracy, h = 4.14×10−15 eV ⋅ s, as stated in the text.The L series of the characteristic x-ray spectrum of tungsten contains wavelengths of 0.1099 nm and 0.1282 nm. The L-shell ionization energy is 11.544 keV. Which x-ray wavelength corresponds to an N → L transition? Determine the ionization energies of the M and N shells: If the incident electrons were accelerated through a 40.00 keV potential difference before striking the target, find the shortest wavelength of the emitted radiation:
- An electron is confined between two perfectly reflecting walls separated by the distance 12 x 10-11m. Use the Heisenberg uncertainty relation to estimate the lowest energy that the particle can have (in eV).A particle is in the n = 9 excited state of a quantum simple harmonic oscillator well. A photon with a frequency of 3.95 x 1015 Hz is emitted as the particle moves to the n = 7 excited state. What is the minimum photon frequency required for this particle to make a quantum jump from the ground state of this well to the n = 8 excited state? (Give your answer in Hz.)The difference in energy between allowed oscillator states in HBr molecules is 0.330 eV. What is the oscillation frequency of this molecule?
- The transition from the first excited state to the ground state in potassium results in the emission of a photon with lambda= 770 nm. If potassium vapor is used in a Franck-Hertz experiment, at what voltage would you expect to see the first decrease in current?An initially stationary electron is accelerated through a voltage 93.6 eV. What is it's de Broglie wavelength, in pm?