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The gravitational potential energy of an object is given by Ug = mgh, where his the object's height above some chosen reference point. An object's kinetic energy is K = 1/2mv^2. Keeping in mind that total energy (U + K) remains constant (assuming no losses due to friction or air resistance), derive an expression that relates the position of the remote on the ramp (in terms of distance from the starting point) to its speed for a given ramp angle.

The gravitational potential energy of an object is given by Ug = mgh, where his the object's height above some chosen reference point. An object's kinetic energy is K = 1/2mv^2. Keeping in mind that total energy (U + K) remains constant (assuming no losses due to friction or air resistance), derive an expression that relates the position of the remote on the ramp (in terms of distance from the starting point) to its speed for a given ramp angle.

Elements Of Electromagnetics
Elements Of Electromagnetics
7th Edition
ISBN:9780190698614
Author:Sadiku, Matthew N. O.
Publisher:Sadiku, Matthew N. O.
ChapterMA: Math Assessment
Section: Chapter Questions
Problem 1.1MA
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The gravitational potential energy of an object is given by Ug = mgh, where his the object's height above some chosen reference point. An object's kinetic energy is K = 1/2mv^2. Keeping in mind that total energy (U + K) remains constant (assuming no losses due to friction or air resistance), derive an expression that relates the position of the remote on the ramp (in terms of distance from the starting point) to its speed for a given ramp angle.
Transcribed Image Text:The gravitational potential energy of an object is given by Ug = mgh, where his the object's height above some chosen reference point. An object's kinetic energy is K = 1/2mv^2. Keeping in mind that total energy (U + K) remains constant (assuming no losses due to friction or air resistance), derive an expression that relates the position of the remote on the ramp (in terms of distance from the starting point) to its speed for a given ramp angle.
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