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The gravitational force exerted by the Sun on the Earth holds the Earth in an orbit around the Sun. Assuming that the Earth orbit is perfectly circular. The work done by this gravitational force during a short time interval in which the Earth moves through a displacement in its orbital path is

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A 2.5 kg mass is initially at rest on a horizontal surface. An applied force acts in the +x direction resulting in a displacement of 1.50 m. If the speed of the mass is 4.00 m/s at the 1.50 m mark, what net work was done?
(Figure 1)A roller-coaster car may be represented by a block of mass 50.0 kg. The car is released from rest at a height h = 54.0 m above the ground and slides along a frictionless track. The car encounters a loop of radius R = 18.0 m at ground level, as shown. As you will learn in the course of this problem, the initial height 54.0 m is great enough so that the car never loses contact with the track. Figure Part A h R M Find the kinetic energy K of the car at the top of the loop. Express your answer numerically, in joules. ▸ View Available Hint(s) K = 8820 J Submit Previous Answers Part B Correct 1 of 1 Find the minimum initial height hmin at which the car can be released that still allows the car to stay in contact with the track at the top of the loop. Express your answer numerically, in meters. ▸ View Available Hint(s) ΕΧΕΙ ΑΣΦ hmin = 72.0 ? m Submit Previous Answers Request Answer × Incorrect; Try Again
A small block with mass m = 17 kg slides on a frictionless track from some initial height through a loop-the-loop with radius R = 6.9 m and then along a flat straight section at the height R/2 above the ground. Assume the block never leaves the smooth track at any point on its path and the track is frictionless What is the minimum speed the block must have at the top of the loop to make it around the loop-the-loop without leaving the track? At what height above the ground must the block begin from rest to make it around the loop-the-loop? It turns out that engineers who designed the loop-the-loop didn’t really know physics – when they made the ride, the initial height was only as high as the top of the loop-the- loop. To account for this honest mistake, they decided to give the block an initial velocity right at the beginning. How fast do they need to push the block at the beginning (now at a height equal to the top of the loop-the-loop) to get it around the loop-the-loop…
The Super Sled travels with an initial kinetic energy of 3369 J horizontally and to the right along a frictionless flat surface, initially at a height of zero (initial gravitational potential energy = 0). The driver briefly engages the rocket over a distance (Ax) of 2.000 m, pushing the sled with a force of 400.0 N over that distance. The rocket is then turned off. The sled then goes up an inclined surface with a rough surface. The coefficient of kinetic friction on the incline is uk. At the top of the incline, the sled reaches a height h = 1.500 m above the ground where the surface becomes flat and frictionless again. The sled (including the rocket and driver) has a total mass of 87.00 kg. (Notes: assume that g = 9.810 m/s² , and that the mass of fuel used by the rocket is negligible. Do not use scientific notation). After &, rocket rocket Before propulsion propulsion starts ends rough inclined surface rocket frictionless engaged coefficient of kinetic friction = H surface h = 1.500 m…
(a) How much gravitational potential energy (relative to the ground on which it is built) is stored in an Egyptian pyramid, given its mass is about 7 ✕ 109 kg and its center of mass is 30.0 m above the surrounding ground? (b) What is the ratio of this energy to the daily food intake of a person (1.2 ✕ 107 J)?
A cord is used to vertically lower an initially stationary block of mass M = 4.9 kg at a constant downward acceleration of g/7. When the block has fallen a distance d = 2.4 m, find (a) the work done by the cord's force on the block, (b) the work done by the gravitational force on the block, (c) the kinetic energy of the block, and (d) the speed of the block. (Note : Take the downward direction positive) (a) Number Units (b) Number Units (c) Number Units (d) Number Units
What formula would I need to use to solve this problem: The rope of a swing is 2.90 m long. Calculate the angle from the vertical at which a 84.0 kg man must begin to swing in order to have the same KE at the bottom as a 1440 kg car moving at 1.41 m/s (3.15 mph). The decrease in gravitational PE is converted into KE as the man falls. This decrease in gravitational PE depends on the change in height.
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A block of mass, m = 0.5 kg is used to compress a spring with a spring con- 78.4 N/m a distance x from it's resting point. The block is then stant, k released and travels towards a circular loop of radius, R = 1.5 m. The loop and the surface as frictionless except for the region, of length 2.5 m, defined by AB which has a coefficient of friction, µk = 0.3. Determine the minimum compression of the spring that allows for the block to just make it through the loop-to-loop at point C (Hint: This problem is best done by starting at the end and working backwards). R k A В
(Figure 1)A roller-coaster car may be represented by a block of mass 50.0 kg. The car is released from rest at a height h = 54.0 m above the ground and slides along a frictionless track. The car encounters a loop of radius R = 18.0 m at ground level, as shown. As you will learn in the course of this problem, the initial height 54.0 m is great enough so that the car never loses contact with the track. a) Find the kinetic energy K of the car at the top of the loop. Express your answer numerically, in joules. b)Find the minimum initial height hmin at which the car can be released that still allows the car to stay in contact with the track at the top of the loop. Express your answer numerically, in meters.
Three different objects, all with different masses, are initially at rest at the bottom of a set of steps. Each step is of uniform height d. The mass of each object is a multiple of the base mass m: object 1 has mass 4.60m, object 2 has mass 2.21m, and object 3 has mass m. When the objects are at the bottom of the steps, define the total gravitational potential energy of the three-object system to be zero. If the objects are then relocated as shown, what is the new total potential energy of the system? Each answer requires the numerical coefficient to an algebraic expression. Each algebraic expression is given using some combination of the variables m, g, and d, where g is the acceleration due to gravity. Enter only the numerical coefficient. (Example: If the answer is 1.23mgd, just enter 1.23) This potential energy was calculated relative to the bottom of the stairs. If you were to redefine the reference height such that the total potential energy of the system became zero, how high…
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