The graph shows how the velocity of a car changes between time t = 0 and a later time tg as the car travels along a straight stretch of highway. The displacement of the car between timet = 0 and time to is -214 m. The values of the velocities and other times indicated or the graph are as follows: t1 10.8 s t2 = 16.3 s t3 = ? t4 = 29.5 s t5 = 35.2 s to = 39 s t7 = 50 s ts = 66 s vo = 14.8 m/s V3 = ?
The graph shows how the velocity of a car changes between time t = 0 and a later time tg as the car travels along a straight stretch of highway. The displacement of the car between timet = 0 and time to is -214 m. The values of the velocities and other times indicated or the graph are as follows: t1 10.8 s t2 = 16.3 s t3 = ? t4 = 29.5 s t5 = 35.2 s to = 39 s t7 = 50 s ts = 66 s vo = 14.8 m/s V3 = ?
College Physics
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Chapter1: Units, Trigonometry. And Vectors
Section: Chapter Questions
Problem 1CQ: Estimate the order of magnitude of the length, in meters, of each of the following; (a) a mouse, (b)...
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![### Analysis of Car Velocity Changes Over Time
The graph shows how the velocity of a car changes between time \( t = 0 \) and a later time \( t_8 \) as the car travels along a straight stretch of highway. The displacement of the car between time \( t = 0 \) and time \( t_6 \) is \(-214 \, \text{m} \). The values of the velocities and other times indicated on the graph are as follows:
- \( t_1 = 10.8 \, \text{s} \)
- \( t_2 = 16.3 \, \text{s} \)
- \( t_3 = ? \)
- \( t_4 = 29.5 \, \text{s} \)
- \( t_5 = 35.2 \, \text{s} \)
- \( t_6 = 39 \, \text{s} \)
- \( t_7 = 50 \, \text{s} \)
- \( t_8 = 66 \, \text{s} \)
- \( v_0 = 14.8 \, \text{m/s} \)
- \( v_3 = ? \)
- \( v_7 = 36.6 \, \text{m/s} \)
#### Tasks to Determine:
(a) **The acceleration of the car at \( t = t_2 \):**
\[ \boxed{ \, \text{m/s}^2 \, } \]](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2F0998dab1-218c-4f1f-b8ec-5be04380a8a9%2Fd646998b-9f99-4990-8360-d445639cc474%2F5zrifpc.png&w=3840&q=75)
Transcribed Image Text:### Analysis of Car Velocity Changes Over Time
The graph shows how the velocity of a car changes between time \( t = 0 \) and a later time \( t_8 \) as the car travels along a straight stretch of highway. The displacement of the car between time \( t = 0 \) and time \( t_6 \) is \(-214 \, \text{m} \). The values of the velocities and other times indicated on the graph are as follows:
- \( t_1 = 10.8 \, \text{s} \)
- \( t_2 = 16.3 \, \text{s} \)
- \( t_3 = ? \)
- \( t_4 = 29.5 \, \text{s} \)
- \( t_5 = 35.2 \, \text{s} \)
- \( t_6 = 39 \, \text{s} \)
- \( t_7 = 50 \, \text{s} \)
- \( t_8 = 66 \, \text{s} \)
- \( v_0 = 14.8 \, \text{m/s} \)
- \( v_3 = ? \)
- \( v_7 = 36.6 \, \text{m/s} \)
#### Tasks to Determine:
(a) **The acceleration of the car at \( t = t_2 \):**
\[ \boxed{ \, \text{m/s}^2 \, } \]

Transcribed Image Text:## Understanding Car Velocity Over Time
The following analysis details how the velocity of a car changes with respect to time as it travels along a straight stretch of highway. This is illustrated through a velocity-time graph.
### Graph Explanation
The graph comprises a horizontal axis labeled \( t \) (time) and a vertical axis labeled \( v(t) \) (velocity). Key points on the graph highlight different velocities and times:
- The vertical points: \( v_0 \) (starting velocity), \( v_3 \) (a lower velocity), and \( v_7 \) (a higher velocity).
- The horizontal points: \( t_1, t_2, t_3, t_4, t_5, t_6, t_7, \) and \( t_8 \), which signify different moments in time.
Initially, the car starts with a velocity of \( v_0 \) at \( t = 0 \). Over time, the car's velocity follows a non-linear trajectory, demonstrating acceleration and deceleration:
1. **From \( t = 0 \) to \( t_1 \)**: The velocity decreases linearly from \( v_0 \) to \( v_3 \).
2. **From \( t_1 \) to \( t_2 \)**: The car maintains a steady velocity of \( v_3 \).
3. **From \( t_2 \) to \( t_3 \)**: The velocity increases linearly toward \( v_0 \).
4. **From \( t_3 \) to \( t_4 \)**: The car maintains the steady velocity \( v_0 \).
5. **From \( t_4 \) to \( t_5 \)**: There is a linear increase in velocity until it reaches \( v_7 \).
6. **From \( t_5 \) to \( t_6 \)**: The velocity decreases back to \( v_0 \).
7. **From \( t_6 \) to \( t_7 \)**: The car maintains a steady velocity of \( v_0 \).
8. **From \( t_7 \) to \( t_8 \)**: The velocity decreases down to 0.
### Provided Data Points
- \( t_1 = 10.8 \) s
- \( t_2 = 16.3 \) s
- \( t_
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