The graph of a function f is shown. 1 Does f satisfy the hypotheses of the Mean Value Theorem on the interval [0, 5]? O Yes, because f is continuous on the closed interval [0, 5] and differentiable on the open interval (0, 5). O Yes, because f is continuous on the open interval (0, 5) and differentiable on the closed interval [0, 5]. O Yes, because f has a maximum on the closed interval [0, 5]. O No, because f does not have a minimum on the closed interval [0, 5]. O No, because f is not differentiable on the open interval (0, 5). O No, because f is not continuous on the open interval (0, 5). If so, find a value c that satisfies the conclusion of the Mean Value Theorem on that interval. (If an answer does not exist, enter DNE.) C =

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