Does the function satisfy the hypotheses of the Mean Value Theorem on the given interval? f(x) = x³ 3x + 5, [-2, 2] O Yes, it does not matter if f is continuous or differentiable; every function satisfies the Mean Value Theorem. O Yes, f is continuous on [-2, 2] and differentiable on (-2, 2) since polynomials are continuous and differentiable on R. O No, f is not continuous on [-2, 2]. O No, f is continuous on [-2, 2] but not differentiable on (-2, 2). O There is not enough information to verify if this function satisfies the Mean Value Theorem.

Advanced Engineering Mathematics
10th Edition
ISBN:9780470458365
Author:Erwin Kreyszig
Publisher:Erwin Kreyszig
Chapter2: Second-order Linear Odes
Section: Chapter Questions
Problem 1RQ
Question
**Does the function satisfy the hypotheses of the Mean Value Theorem on the given interval?**

\( f(x) = x^3 - 3x + 5 \), \([-2, 2]\)

1. ○ Yes, it does not matter if \( f \) is continuous or differentiable; every function satisfies the Mean Value Theorem.
2. ○ Yes, \( f \) is continuous on \([-2, 2]\) and differentiable on \((-2, 2)\) since polynomials are continuous and differentiable on \(\mathbb{R}\).
3. ○ No, \( f \) is not continuous on \([-2, 2]\).
4. ○ No, \( f \) is continuous on \([-2, 2]\) but not differentiable on \((-2, 2)\).
5. ○ There is not enough information to verify if this function satisfies the Mean Value Theorem.

**If it satisfies the hypotheses, find all numbers \( c \) that satisfy the conclusion of the Mean Value Theorem.** (Enter your answers as a comma-separated list. If it does not satisfy the hypotheses, enter DNE).
Transcribed Image Text:**Does the function satisfy the hypotheses of the Mean Value Theorem on the given interval?** \( f(x) = x^3 - 3x + 5 \), \([-2, 2]\) 1. ○ Yes, it does not matter if \( f \) is continuous or differentiable; every function satisfies the Mean Value Theorem. 2. ○ Yes, \( f \) is continuous on \([-2, 2]\) and differentiable on \((-2, 2)\) since polynomials are continuous and differentiable on \(\mathbb{R}\). 3. ○ No, \( f \) is not continuous on \([-2, 2]\). 4. ○ No, \( f \) is continuous on \([-2, 2]\) but not differentiable on \((-2, 2)\). 5. ○ There is not enough information to verify if this function satisfies the Mean Value Theorem. **If it satisfies the hypotheses, find all numbers \( c \) that satisfy the conclusion of the Mean Value Theorem.** (Enter your answers as a comma-separated list. If it does not satisfy the hypotheses, enter DNE).
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