The graph illustrates a normal distribution for the prices paid for a particular model of HD television. The mean price paid is $1800 and the standard deviation is $85. 1630 1715 1800 1885 1970 2055 Distribution of Prices What is the approximate percentage of buyers who paid between $1715 and $1800? What is the approximate percentage of buyers who paid more than $2055? What is the approximate percentage of buyers who paid more than $1970?

Glencoe Algebra 1, Student Edition, 9780079039897, 0079039898, 2018
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Chapter4: Equations Of Linear Functions
Section4.5: Correlation And Causation
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The graph illustrates a normal distribution for the prices paid for a particular model of HD television. The mean price paid is $1800 and the standard deviation is $85.

The bell curve shown represents the distribution of prices. On the horizontal axis, various price points are marked, ranging from $1545 to $2055. The prices increase from left to right following the pattern 1545, 1630, 1715, 1800 (which is the mean), 1885, 1970, and 2055.

### Questions:

1. What is the approximate percentage of buyers who paid between $1715 and $1800?
   - [Text Box] %

2. What is the approximate percentage of buyers who paid more than $2055?
   - [Text Box] %

3. What is the approximate percentage of buyers who paid more than $1970?
   - [Text Box] %

4. What is the approximate percentage of buyers who paid between $1630 and $1800?
   - [Text Box] %

5. What is the approximate percentage of buyers who paid between $1545 and $1800?
   - [Text Box] %

6. What is the approximate percentage of buyers who paid between $1715 and $1885?
   - [Text Box] %

### Explanation of the Graph:

- **Mean ($1800)**: The peak of the bell curve is at $1800, indicating this is the average price paid.
- **$85 Standard Deviation**: Each tick mark along the horizontal axis represents one standard deviation from the mean. 
  - $1715 ($1800 - $85)
  - $1630 ($1800 - 2* $85)
  - $1545 ($1800 - 3* $85)
  - $1885 ($1800 + $85)
  - $1970 ($1800 + 2* $85)
  - $2055 ($1800 + 3* $85)

The normal distribution curve helps to understand the distribution of different price ranges paid by consumers. For example, the area under the curve between two price points represents the percentage of users who paid within that range. As one moves away from the mean, the percentage of buyers decreases.
Transcribed Image Text:The graph illustrates a normal distribution for the prices paid for a particular model of HD television. The mean price paid is $1800 and the standard deviation is $85. The bell curve shown represents the distribution of prices. On the horizontal axis, various price points are marked, ranging from $1545 to $2055. The prices increase from left to right following the pattern 1545, 1630, 1715, 1800 (which is the mean), 1885, 1970, and 2055. ### Questions: 1. What is the approximate percentage of buyers who paid between $1715 and $1800? - [Text Box] % 2. What is the approximate percentage of buyers who paid more than $2055? - [Text Box] % 3. What is the approximate percentage of buyers who paid more than $1970? - [Text Box] % 4. What is the approximate percentage of buyers who paid between $1630 and $1800? - [Text Box] % 5. What is the approximate percentage of buyers who paid between $1545 and $1800? - [Text Box] % 6. What is the approximate percentage of buyers who paid between $1715 and $1885? - [Text Box] % ### Explanation of the Graph: - **Mean ($1800)**: The peak of the bell curve is at $1800, indicating this is the average price paid. - **$85 Standard Deviation**: Each tick mark along the horizontal axis represents one standard deviation from the mean. - $1715 ($1800 - $85) - $1630 ($1800 - 2* $85) - $1545 ($1800 - 3* $85) - $1885 ($1800 + $85) - $1970 ($1800 + 2* $85) - $2055 ($1800 + 3* $85) The normal distribution curve helps to understand the distribution of different price ranges paid by consumers. For example, the area under the curve between two price points represents the percentage of users who paid within that range. As one moves away from the mean, the percentage of buyers decreases.
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