The graph illustrates a normal distribution for the prices paid for a particular model of HD television. Themean price paid is $2000 and the standard deviation is $75.1775185019252000207521502225Distribution of PricesWhat is the approximate percentage of buyers who paid more than $2225?What is the approximate percentage of buyers who paid between $1925 and $2075?What is the approximate percentage of buyers who paid less than $1850?What is the approximate percentage of buyers who paid between $1775 and $2000?What is the approximate percentage of buyers who paid between $1850 and $2000?What is the approximate percentage of buyers who paid between $2000 and $2075?

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Answered: The graph illustrates a normal…

MATLAB: An Introduction with Applications

6th Edition

ISBN:9781119256830

Author:Amos Gilat

Publisher:Amos Gilat

Chapter1: Starting With Matlab

Section: Chapter Questions

Problem 1P

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The graph illustrates a normal distribution for the prices paid for a particular model of HD television. The mean price paid is $1400 and the standard deviation is $75. 1175 1250 1325 1400 1475 1550 1625 Distribution of Prices What is the approximate percentage of buyers who paid between $1400 and $1625? What is the approximate percentage of buyers who paid between $1400 and $1550? What is the approximate percentage of buyers who paid more than $1550? What is the approximate percentage of buyers who paid less than $1175? What is the approximate percentage of buyers who paid between $1325 and $1475? What is the approximate percentage of buyers who paid between $1400 and $14752
The graph illustrates a normal distribution for the prices paid for a particular model of HD television. The mean price paid is $1400 and the standard deviation is $50.What is the approximate percentage of buyers who paid between $1350 and $1450?%What is the approximate percentage of buyers who paid between $1350 and $1400?%What is the approximate percentage of buyers who paid between $1400 and $1500?%What is the approximate percentage of buyers who paid between $1250 and $1400?%What is the approximate percentage of buyers who paid more than $1500?%What is the approximate percentage of buyers who paid less than $1250?%
Suppose you have already calculated the mean, the average deviation, and the standard deviation of the weights in pounds of 20 third-graders. a. if these weights were converted to kilograms and the mean and the average deviation were once again calculated, would the second average deviation be (numerically) less than, greater than, or equal to the first average deviation? Explain your answer. b. If the standard deviation of these weights were calculated in kilograms, would it be (numerically) less than, greater than, or equal to the first standard deviation? Explain your answer
(See photo) The data set on the left represents the annual rate of return (in percent) of eight randomly sampled bond mutual funds, and the data set on the right represents the annual rate of return (in percent) of eight randomly sampled stock mutual funds. What proportion of the observations is within one standard deviation of the mean for each data set?
The graph illustrates a normal distribution for the prices paid for a particular model of HD television. The mean price paid is $1600 and the standard deviation is $140.What is the approximate percentage of buyers who paid less than $1320? What is the approximate percentage of buyers who paid less than $1180?
I was wondering if these answers are correct. Explain. A study by Quadrant Information Services commissioned by Insure.com calculated auto insurance rates for each of the 50 states; and as a result, the average annual rate for the United States was $1,317. Suppose annual rates of auto insurance in the United States are normally distributed with a standard deviation of $324. According to MoneyGeek, a state minimum auto insurance policy in Florida costs an average of $1123 per year and the average cost of full coverage car insurance in Florida is $2208. What percentage of policies cost less than the Florida state minimum policy of $1123? z = (x - mu) / sigma z = (1123-1317)/324 z= -0.59876543 P-value from Z-Table: P(x<1123) = 0.27466 The answer is less than I expected. After using a z-table to determine the score it results in 27% of policies that are less than the minimum policy of 1123. What percentage of auto insurance rates would be less than $1,200? z = (x - mu) / sigma…
The graph illustrates a normal distribution for the prices paid for a particular model of HD television. The mean price paid is $2000 and the standard deviation is $80 1760 1840 1920 2000 2080 2160 2240 Distribution of Prices What is the approximate percentage of buyers who paid between $2000 and S2160? 9% What is the approximate percentage of buyers who paid between $1920 and $2080? 0 0 What is the approximate percentage of buyers who paid between $2000 and S2080? 0 0 What is the approximate percentage of buyers who paid more than $2160 0 What is the approximate percentage of buyers who paid berween $2000 and $2240? 0 What is the approximate percentage of buyers m ho paid less than $1760?
Itemized Charitable Contributions The average charitable contribution itemized per income tax return in Pennsylvania is $792. Suppose that the distribution of contributions is normal with a standard deviation of $105. Find the limits for the middle 42% of contributions. Use a graphing calculator and round the answers to two decimal places. The limits for the middle 42% of contributions are $ and $ %24
The graph shows the distribution of the lengths (in seconds) of videos on a popular video-streaming site. The distribution is approximately Normal, with a mean What percentage of videos on the streaming site are between 264 and 489 seconds? 0.15% of 264 seconds and a standard deviation of 75 seconds. 49.85% 95% Streaming Videos 99.7% 36 30 114 189 264 339 414 489 564 Mark this and return Save and Exit Next Submit Previous Activity Next Activity
In some reports, the mean and coefficient of variation are given. For instance, one report gives the average number of physician visits by males per year. The average reported is 2.6, and the reported coefficient of variation is 2.3%. Use this information to determine the standard deviation of the annual number of visits to physicians made by males. (Round your answer to three decimal places.)

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