The graph below shows the titration of the aqueous solution containing 0.168 g of unknown monoprotic acid solution with 0.0995M NaOH. Use the proper graphing techniques to find the equivalence and half-equivalence points and determine the pKa and Ka of an unknown acid.  equivalence point:          VNaOH=                          pH= half-equivalence point: VNaOH=                          pH=                                             pKa=                                                                           Ka=                                  Taking into account that the mass of the weak monoprotic acid used in the titration was 0.168 g, calculate the molar mass (MM)  and identify the weak acid  MM=                                                           Identification of acid:

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The graph below shows the titration of the aqueous solution containing 0.168 g of unknown monoprotic acid solution with 0.0995M NaOH.

Use the proper graphing techniques to find the equivalence and half-equivalence points and determine the pKa and Ka of an unknown acid. 

equivalence point:          VNaOH=                          pH=

half-equivalence point: VNaOH=                          pH=

                                            pKa=                             

                                             Ka=                                 

Taking into account that the mass of the weak monoprotic acid used in the titration was 0.168 g, calculate the molar mass (MM)  and identify the weak acid 

MM=                                                           Identification of acid:

 

PH
14
12
10
8
6
S
4
2
0
0
10
Acid-Base Titration Curve
20
30
ml NaOH
40
50
60
Series1
Transcribed Image Text:PH 14 12 10 8 6 S 4 2 0 0 10 Acid-Base Titration Curve 20 30 ml NaOH 40 50 60 Series1
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