The graph below represents the relationship between the current in a metallic conductor and the potential difference across the conductor at constant temperature. The resistance of the conductor is Current vs. Potential Difference 2.0 1.5 1.0 0.5 1.0 2.0 3.o 4.0 5.0 Potential Difference (V) O 1.0 0 2.0 Q O 0.50 Q O 4.0 0 Current (A)
The graph below represents the relationship between the current in a metallic conductor and the potential difference across the conductor at constant temperature. The resistance of the conductor is Current vs. Potential Difference 2.0 1.5 1.0 0.5 1.0 2.0 3.o 4.0 5.0 Potential Difference (V) O 1.0 0 2.0 Q O 0.50 Q O 4.0 0 Current (A)
College Physics
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ISBN:9781305952300
Author:Raymond A. Serway, Chris Vuille
Publisher:Raymond A. Serway, Chris Vuille
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![### Topic: Ohm's Law
**Graph Explanation**
The graph below represents the relationship between the current in a metallic conductor and the potential difference across the conductor at constant temperature. The resistance of the conductor is to be determined.
**Graph Details**
- **Title**: Current vs. Potential Difference
- **X-axis (Horizontal)**: Potential Difference (V) ranging from 0 to 5 volts.
- **Y-axis (Vertical)**: Current (A) ranging from 0 to 2 amperes.
- **Data Representation**: The graph displays a straight line passing through the origin with a positive slope, indicating a direct proportional relationship between current and potential difference.
### Analysis
Ohm’s Law states that the Current (I) through a conductor between two points is directly proportional to the Voltage (V) across the two points.
\[ V = I \cdot R \]
where \( R \) is the resistance.
From the graph, observe the slope \( (m) \):
\[ m = \frac{\Delta I}{\Delta V} \]
Choose two points from the graph:
- Point 1: (1 V, 0.5 A)
- Point 2: (4 V, 2 A)
Calculate the slope:
\[ \text{Slope} = \frac{2 A - 0.5 A}{4 V - 1 V} = \frac{1.5 A}{3 V} = 0.5 \, \Omega^{-1} \]
The resistance \( R \) is the reciprocal of the slope:
\[ R = \frac{1}{\text{Slope}} = \frac{1}{0.5 \, \Omega^{-1}} = 2 \, \Omega \]
### Question
Determine the resistance of the conductor. Choose one:
- [ ] 1.0 Ω
- [x] 2.0 Ω
- [ ] 0.50 Ω
- [ ] 4.0 Ω](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2F2b2979df-2aee-456c-8524-93187fc3ab50%2F66406c63-d0c8-4f2f-97ae-9cce7f94099e%2F8ucsm6o_processed.jpeg&w=3840&q=75)
Transcribed Image Text:### Topic: Ohm's Law
**Graph Explanation**
The graph below represents the relationship between the current in a metallic conductor and the potential difference across the conductor at constant temperature. The resistance of the conductor is to be determined.
**Graph Details**
- **Title**: Current vs. Potential Difference
- **X-axis (Horizontal)**: Potential Difference (V) ranging from 0 to 5 volts.
- **Y-axis (Vertical)**: Current (A) ranging from 0 to 2 amperes.
- **Data Representation**: The graph displays a straight line passing through the origin with a positive slope, indicating a direct proportional relationship between current and potential difference.
### Analysis
Ohm’s Law states that the Current (I) through a conductor between two points is directly proportional to the Voltage (V) across the two points.
\[ V = I \cdot R \]
where \( R \) is the resistance.
From the graph, observe the slope \( (m) \):
\[ m = \frac{\Delta I}{\Delta V} \]
Choose two points from the graph:
- Point 1: (1 V, 0.5 A)
- Point 2: (4 V, 2 A)
Calculate the slope:
\[ \text{Slope} = \frac{2 A - 0.5 A}{4 V - 1 V} = \frac{1.5 A}{3 V} = 0.5 \, \Omega^{-1} \]
The resistance \( R \) is the reciprocal of the slope:
\[ R = \frac{1}{\text{Slope}} = \frac{1}{0.5 \, \Omega^{-1}} = 2 \, \Omega \]
### Question
Determine the resistance of the conductor. Choose one:
- [ ] 1.0 Ω
- [x] 2.0 Ω
- [ ] 0.50 Ω
- [ ] 4.0 Ω
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