A symmetrical parabolic curve passes through point A whose elevation is 23 23m at a distance of 54 meters from PC The elevation of the P.C. at station 4+100 is 22.56m. The grade of the back tangent is +2% and the length of the curve is 120m. Determine the grade of the forward tangent a. -2.3% b. -1.4% c. -3.3% d. 2.5%

Q: The tangents of a sag curve connects at the point of intersection having Station 18+448 and…

A:

Q: For vertical alignment with one equal tangent vertical curve where g1 = -5%, g2 = +7%, L = 300.00…

A: Vertical alignment is the alignment of a pipe in the vertical direction with respect to the required…

Q: Problem 4 A vertical summit parabolic has its P.I. at station 12 + 750 with elevation of 77.30 m.…

A: Given Data:Station of PV1=12+750Elevation Pv1=77.30mForward Tangent g2=-3.8%back tangent…

Q: A - 6% grade and a + 2% grade intersect at sta. 12 + 200 whose elevation is at 45.673 m. The two…

A: PVCELV=PVIELV-g1L2PVCelv=45.673+0.06×1802PVCelv=51.073m

Q: A vertical crest curve has an approach grade +3% and a departure grade –3%. The VIP level is 120 m…

A: To calculate 'H' based on the given data we have  2HL2= (g1 -g2)L2L g1 = 3% = 0.03 g2 = -3% = - 0.03…

Q: A 850-ft equal-tangent creat vertical cuve has its PVC at station 102+00 and elevation 1000 ft. The…

A: g1 = 3.5%g2 = - 3 %Length of curve (L) = 850 ft

Q: 1-A back tangent line that bears N 45 E meets a forward tangent line with a direction of N 85 E. The…

A: Reference : Survey Engineering, Curve Analysis. Given : Back tangent, Direction and location of…

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