The GPS network consists of 24 satellites, each of which makes two orbits around the earth per day. Each satellite transmits a 50.0-W (or even less) sinusoidal electromagnetic signal at two frequencies, one of which is 1575.42 MHz. Assume that a satellite transmits half of its power at each frequency and that the waves travel uniformly in a downward hemisphere. Submit Previous Answers ✓ Correct Correct answer is shown. Your answer 9.73-10-15 =9.73x10-15 W/m² was either rounded differently or number of significant figures than required for this part. Part B
The GPS network consists of 24 satellites, each of which makes two orbits around the earth per day. Each satellite transmits a 50.0-W (or even less) sinusoidal electromagnetic signal at two frequencies, one of which is 1575.42 MHz. Assume that a satellite transmits half of its power at each frequency and that the waves travel uniformly in a downward hemisphere. Submit Previous Answers ✓ Correct Correct answer is shown. Your answer 9.73-10-15 =9.73x10-15 W/m² was either rounded differently or number of significant figures than required for this part. Part B
Related questions
Question
100%
D,E,F
![Below is a detailed transcription of the image content suitable for an educational website:
---
### GPS Satellite Network Analysis
**Background Information:**
The GPS network consists of 24 satellites, each of which makes two orbits around the Earth per day. Each satellite transmits a 50.0 W (or even less) sinusoidal electromagnetic signal at two frequencies, one of which is 1575.42 MHz. Assume that a satellite transmits half of its power at each frequency and that the waves travel uniformly in a downward hemisphere.
**Part A: Intensity Calculation**
The satellite signal intensity at the receiver is given as:
\[ I = 9.75 \times 10^{-15} \, \text{W/m}^2 \]
*Feedback:*
- **Correct!**
- The correct answer shown is:
\[ I = 9.73 \times 10^{-15} \, \text{W/m}^2 \]
- The given value of \( 9.73 \times 10^{-15} = 9.73 \times 10^{-15} \, \text{W/m}^2 \) was either rounded differently or used a different number of significant figures than required for this part.
**Part B: Electric Field Amplitude Calculation**
What is the amplitude of the electric field at the GPS receiver in part (a)?
\[ E_{\text{max}} = 2.71 \times 10^{-6} \, \text{N/C} \]
*Feedback:*
- **Correct!**
**Part C: Magnetic Field Amplitude Calculation**
What is the amplitude of the magnetic field at the GPS receiver in part (a)?
\[ B_{\text{max}} = 9.03 \times 10^{-15} \, \text{T} \]
*Feedback:*
- **Correct!**
---
This detailed transcription not only explains the given answers but also breaks down the problem into distinct segments, explaining each step clearly and concisely for educational purposes.](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2F8d4f1709-330a-4d41-ae4f-aad2db91bb03%2F4e3e24c8-c6fc-4b5c-8759-e2e74f99bcb5%2F9vzsl8n_processed.png&w=3840&q=75)
Transcribed Image Text:Below is a detailed transcription of the image content suitable for an educational website:
---
### GPS Satellite Network Analysis
**Background Information:**
The GPS network consists of 24 satellites, each of which makes two orbits around the Earth per day. Each satellite transmits a 50.0 W (or even less) sinusoidal electromagnetic signal at two frequencies, one of which is 1575.42 MHz. Assume that a satellite transmits half of its power at each frequency and that the waves travel uniformly in a downward hemisphere.
**Part A: Intensity Calculation**
The satellite signal intensity at the receiver is given as:
\[ I = 9.75 \times 10^{-15} \, \text{W/m}^2 \]
*Feedback:*
- **Correct!**
- The correct answer shown is:
\[ I = 9.73 \times 10^{-15} \, \text{W/m}^2 \]
- The given value of \( 9.73 \times 10^{-15} = 9.73 \times 10^{-15} \, \text{W/m}^2 \) was either rounded differently or used a different number of significant figures than required for this part.
**Part B: Electric Field Amplitude Calculation**
What is the amplitude of the electric field at the GPS receiver in part (a)?
\[ E_{\text{max}} = 2.71 \times 10^{-6} \, \text{N/C} \]
*Feedback:*
- **Correct!**
**Part C: Magnetic Field Amplitude Calculation**
What is the amplitude of the magnetic field at the GPS receiver in part (a)?
\[ B_{\text{max}} = 9.03 \times 10^{-15} \, \text{T} \]
*Feedback:*
- **Correct!**
---
This detailed transcription not only explains the given answers but also breaks down the problem into distinct segments, explaining each step clearly and concisely for educational purposes.
Transcribed Image Text:### Question Transcriptions for Educational Website
#### How long does it take the signal to reach the receiver?
- **Prompt:**
- How long does it take the signal to reach the receiver?
- **Input Field:**
- \( t = \ \text{s} \)
- **Buttons:**
- Submit
- Request Answer
#### Part E
- **Question:**
- If the receiver is a square panel \(2.50 \ \text{cm}\) on a side that absorbs all of the beam, what average pressure does the signal exert on it?
- **Input Field:**
- \( P_{av} = \ \text{Pa} \)
- **Buttons:**
- Submit
- Request Answer
#### Part F
- **Question:**
- What wavelength must the receiver be tuned to?
- **Input Field:**
- Blank input field
- **Buttons:**
- Submit
- Request Answer
Expert Solution
This question has been solved!
Explore an expertly crafted, step-by-step solution for a thorough understanding of key concepts.
This is a popular solution!
Trending now
This is a popular solution!
Step by step
Solved in 2 steps with 2 images
