Another exemplary application for AV Bc :AVBC through B→N,→N,→C: AV BC = R4I, + R3I, + R,IAVBC through B→A→N,→C: AV Bc = V1 – R¡I, + R,I1AVBc through B→N,→D→C:AV BC = R,I, – R3I, + V21Line 6: Express AVAD similarly, through A→N,→N,→D. AVADLine 7: Express AVAD similarly, through A→B→N,→D. AV ADLine 8: Express AVAD similarly, through A→N,→C→D. AV AD RyR2AwwR3V, IR.R.wwwwDN2B

here voltage drop take negative if we move in the direction of current = -IR and take positive if…

Answered: Line 6: Express AV AD similarly,…

Line 6: Express AV AD similarly, through A→N,→N,¬D. AV AD Line 7: Express AV AD similarly, through A→B→N,→D. AV, AD Line 8: Express AV AD similarly, through A→N,→C→D. AV AD

College Physics

11th Edition

ISBN:9781305952300

Author:Raymond A. Serway, Chris Vuille

Publisher:Raymond A. Serway, Chris Vuille

Chapter1: Units, Trigonometry. And Vectors

Section: Chapter Questions

Problem 1CQ: Estimate the order of magnitude of the length, in meters, of each of the following; (a) a mouse, (b)...

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Question

Another exemplary application for AV Bc :
AV
BC through B→N,→N,→C: AV BC = R4I, + R3I, + R,I
AV
BC through B→A→N,→C: AV Bc = V1 – R¡I, + R,I1
AV
Bc through B→N,→D→C:AV BC = R,I, – R3I, + V2
1
Line 6: Express AV
AD similarly, through A→N,→N,→D. AV
AD
Line 7: Express AV
AD similarly, through A→B→N,→D. AV AD
Line 8: Express AV
AD similarly, through A→N,→C→D. AV AD

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