import java.util.Scanner;import java.util.InputMismatchException;public class NameAgeChecker { public static void main(String[] args) { Scanner scnr = new Scanner(System.in); String inputName; int age; inputName = scnr.next(); while (!inputName.equals("-1")) { // FIXME: The following line will throw an InputMismatchException. // Insert a try/catch statement to catch the exception. age = scnr.nextInt(); System.out.println(inputName + " " + (age + 1)); inputName = scnr.next(); } }} 3.7 LAB: Exception handling to detect input String vs. IntegerThe given program reads a list of single-word first names and ages (ending with -1), and outputs that list with the age incremented. Theprogram fails and throws an exception if the second input on a line is a String rather than an Integer. At FIXME in the code, add a try/catchstatement to catch java.util. Input Mismatch Exception, and output 0 for the age.Ex: If the input is:Lee 18.Lua 21Mary Beth 19Stu 33-1then the output is:Lee 19Lua 22Mary 0Stu 34430560.2938290.qx3zqy7LABACTIVITY4 public class NameAgeChecker {568910113.7.1: LAB: Exception handling to detect input String vs. Integer121314public static void main(String[] args) {Scanner scnr = new Scanner(System.in);String inputName;int age;NameAgeChecker.javainputName = scnr.next();while (!inputName.equals("-1")) {// FIXME: The following line will throw an InputMismatch Exception.//Insert a try/catch statement to catch the exception.-In+/)0/10Load default template...

Answered: The given program reads a list of…

Database System Concepts

7th Edition

ISBN:9780078022159

Author:Abraham Silberschatz Professor, Henry F. Korth, S. Sudarshan

Publisher:Abraham Silberschatz Professor, Henry F. Korth, S. Sudarshan

Chapter1: Introduction

Section: Chapter Questions

Problem 1PE

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Question

import java.util.Scanner;
import java.util.InputMismatchException;

public class NameAgeChecker {
public static void main(String[] args) {
Scanner scnr = new Scanner(System.in);

String inputName;
int age;

inputName = scnr.next();
while (!inputName.equals("-1")) {
// FIXME: The following line will throw an InputMismatchException.
// Insert a try/catch statement to catch the exception.
age = scnr.nextInt();
System.out.println(inputName + " " + (age + 1));

inputName = scnr.next();
}
}
}

3.7 LAB: Exception handling to detect input String vs. Integer
The given program reads a list of single-word first names and ages (ending with -1), and outputs that list with the age incremented. The
program fails and throws an exception if the second input on a line is a String rather than an Integer. At FIXME in the code, add a try/catch
statement to catch java.util. Input Mismatch Exception, and output 0 for the age.
Ex: If the input is:
Lee 18.
Lua 21
Mary Beth 19
Stu 33
-1
then the output is:
Lee 19
Lua 22
Mary 0
Stu 34
430560.2938290.qx3zqy7
LAB
ACTIVITY
4 public class NameAgeChecker {
5
6
8
9
10
11
3.7.1: LAB: Exception handling to detect input String vs. Integer
12
13
14
public static void main(String[] args) {
Scanner scnr = new Scanner(System.in);
String inputName;
int age;
NameAgeChecker.java
inputName = scnr.next();
while (!inputName.equals("-1")) {
// FIXME: The following line will throw an InputMismatch Exception.
//
Insert a try/catch statement to catch the exception.
-In+/)
0/10
Load default template...

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