The given frame is subjected to the applied loads P and Q. Note that members ABC and CDE are pin-connected at C. a) Draw the FBDs of all members. A b) Determine the force in each link (AF, BG, DG, and EH). Neglect the weight of the members. Parameters * * 2 0 A B C 2 3 P=100+ (ECD) x 0.1 Q = 100+ (BAC) x 0.1 e = 30 x (P/Q) 2 0 2 P=100+ (534) x 0.1 = 153.4 kN Q=100+ (312) x 0.1 = 121.3 kN e 30 x (153.4/121.3) = 37.94° = D4 E5 5 2a I B W 7 a I (0) I HE C D 8 a a 2a
The given frame is subjected to the applied loads P and Q. Note that members ABC and CDE are pin-connected at C. a) Draw the FBDs of all members. A b) Determine the force in each link (AF, BG, DG, and EH). Neglect the weight of the members. Parameters * * 2 0 A B C 2 3 P=100+ (ECD) x 0.1 Q = 100+ (BAC) x 0.1 e = 30 x (P/Q) 2 0 2 P=100+ (534) x 0.1 = 153.4 kN Q=100+ (312) x 0.1 = 121.3 kN e 30 x (153.4/121.3) = 37.94° = D4 E5 5 2a I B W 7 a I (0) I HE C D 8 a a 2a
Chapter2: Loads On Structures
Section: Chapter Questions
Problem 1P
Related questions
Question
![The given frame is subjected to the applied loads P and Q.
Note that members ABC and CDE are pin-connected at C.
a) Draw the FBDs of all members.
A
b) Determine the force in each link (AF, BG, DG, and EH).
F
Neglect the weight of the members.
Parameters
*
2 0
D
A B C
1
2 10 2 1
3
P= 100+ (ECD) x 0.1
Q = 100+ (BAC) x 0.1
e = 30 x (P/Q)
P = 100 + (534) x 0.1 = 153.4 kN
Q=100+ (312) x 0.1 = 121.3 kN
e = 30 x (153.4/121.3) = 37.94°
14
E5
E
2a
B
3
OG
HO
HE
D
8
a
2a](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2F3234784c-761d-4927-b651-dd8d2a9c02f1%2Fb7008a56-eb78-4478-9542-5175a4ce9590%2Fugon0y_processed.jpeg&w=3840&q=75)
Transcribed Image Text:The given frame is subjected to the applied loads P and Q.
Note that members ABC and CDE are pin-connected at C.
a) Draw the FBDs of all members.
A
b) Determine the force in each link (AF, BG, DG, and EH).
F
Neglect the weight of the members.
Parameters
*
2 0
D
A B C
1
2 10 2 1
3
P= 100+ (ECD) x 0.1
Q = 100+ (BAC) x 0.1
e = 30 x (P/Q)
P = 100 + (534) x 0.1 = 153.4 kN
Q=100+ (312) x 0.1 = 121.3 kN
e = 30 x (153.4/121.3) = 37.94°
14
E5
E
2a
B
3
OG
HO
HE
D
8
a
2a
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