The given equation is balanced in acidic condition. The steps to balance in basic condition would be: CIO3¹ +6 Br¹ + 6 H+¹ →CI-¹ + 3 Br₂ + 3 H₂O -1 A. Add OH´ to both sides of the equation. B. Add 6 OH to the left side of the equation. Then, subtract the waters from both sides of the equation. C. Add 6 OH-1 to the right side of the equation and add the H₂O with the OH´to make more water. -1 to both sides of the equation and add to make 6 H₂O. Then, add to D. Add 6 OH make more water. E. Add 6 OH-¹ to both sides of the equation and add to make 6 H₂O. Then, subtract the waters. B
The given equation is balanced in acidic condition. The steps to balance in basic condition would be: CIO3¹ +6 Br¹ + 6 H+¹ →CI-¹ + 3 Br₂ + 3 H₂O -1 A. Add OH´ to both sides of the equation. B. Add 6 OH to the left side of the equation. Then, subtract the waters from both sides of the equation. C. Add 6 OH-1 to the right side of the equation and add the H₂O with the OH´to make more water. -1 to both sides of the equation and add to make 6 H₂O. Then, add to D. Add 6 OH make more water. E. Add 6 OH-¹ to both sides of the equation and add to make 6 H₂O. Then, subtract the waters. B
Chemistry
10th Edition
ISBN:9781305957404
Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Publisher:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Chapter1: Chemical Foundations
Section: Chapter Questions
Problem 1RQ: Define and explain the differences between the following terms. a. law and theory b. theory and...
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Transcribed Image Text:D
The given equation is balanced in acidic condition. The steps to balance in basic
condition would be:
CIO3-¹ + 6 Br¹ +6 H¹ →CI-¹ + 3 Br₂ + 3 H₂O
-1
A. Add OH to both sides of the equation.
B. Add 6 OH to the left side of the equation. Then, subtract the waters from both
sides of the equation.
C. Add 6 OH¹ to the right side of the equation and add the H₂O with the OH to
make more water.
D. Add 6 OH to both sides of the equation and add to make 6 H₂O. Then, add to
make more water.
to both sides of the equation and add to make 6 H₂O. Then, subtract
E. Add 6 OH
the waters.
B
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