The given block diagram below represents the velocity control of a DC motor using armature voltage control. TL(s) R(s) W(s) 1 Go Km Ls+R Js+B Kp H Where Ge is the controller transfer function, H is the feedback path gain, R(s) is the reference input, TL(s) is the load torque and w(s) is the motor speed. Assume, for the ease of computation, L = 2, R= 1, J= 1, B= 3. 10) If the motor has to controlled such that it has zero speed for a given load torque, i.e. R(s) = 0, how sensitive will the closed loop transfer function be to changes in the feedback gain H? HG Km 2s2 + 7s +3+ G.HKm + KmK, -(2s + 1) 2s2 + 78 +3+ G.HKm + KmK, 2s +1 2s2 + 7s +3+ G.HKm + Km K, -HG Km 2s2 + 7s +3+ G.HKm + Km K,

Introductory Circuit Analysis (13th Edition)
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ISBN:9780133923605
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Publisher:Robert L. Boylestad
Chapter1: Introduction
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The given block diagram below represents the velocity control of a DC motor using armature voltage control.
TL(s)
R(s)
W(s)
1
Go
Km
Ls+R
Js+B
H
Where Ge is the controller transfer function, H is the feedback path gain, R(s) is the reference input, TL(s) is the load torque and w(s) is the motor speed.
Assume, for the ease of computation, L = 2, R= 1, J= 1, B= 3.
10) If the motor has to controlled such that it has zero speed for a given load torque, i.e. R(s) = 0, how sensitive will the closed loop transfer
function be to changes in the feedback gain H?
HG Km
2s2 + 7s +3+ G.HKm + KmK,
-(2s +1)
2s2 + 7s +3+ G.HKm + KmK,
2s +1
2s2 + 78 +3+ G.HKm + Km K,
-HG Km
2s2 + 7s +3+ G.HKm + Km K,
Transcribed Image Text:The given block diagram below represents the velocity control of a DC motor using armature voltage control. TL(s) R(s) W(s) 1 Go Km Ls+R Js+B H Where Ge is the controller transfer function, H is the feedback path gain, R(s) is the reference input, TL(s) is the load torque and w(s) is the motor speed. Assume, for the ease of computation, L = 2, R= 1, J= 1, B= 3. 10) If the motor has to controlled such that it has zero speed for a given load torque, i.e. R(s) = 0, how sensitive will the closed loop transfer function be to changes in the feedback gain H? HG Km 2s2 + 7s +3+ G.HKm + KmK, -(2s +1) 2s2 + 7s +3+ G.HKm + KmK, 2s +1 2s2 + 78 +3+ G.HKm + Km K, -HG Km 2s2 + 7s +3+ G.HKm + Km K,
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