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The general solution of the fourth-order differential equation y() + y" +y"-0 is: y=c_1 +c_2 x+e^((-x)/2) (c_3 cos((V3/2) x)+c_4 sin((v3/2) x) y=c_1 +c_2 x+e^((-x)/2) (c_3 cos((V3) x)+c_4 sin((v3) x) y=c_1 +c_2 x+e^((x)/2) (c_3 cos((v3/2)

The general solution of the fourth-order differential equation y() + y" +y"-0 is: y=c_1 +c_2 x+e^((-x)/2) (c_3 cos((V3/2) x)+c_4 sin((v3/2) x) y=c_1 +c_2 x+e^((-x)/2) (c_3 cos((V3) x)+c_4 sin((v3) x) y=c_1 +c_2 x+e^((x)/2) (c_3 cos((v3/2)

Calculus: Early Transcendentals
Calculus: Early Transcendentals
8th Edition
ISBN:9781285741550
Author:James Stewart
Publisher:James Stewart
Chapter1: Functions And Models
Section: Chapter Questions
Problem 1RCC: (a) What is a function? What are its domain and range? (b) What is the graph of a function? (c) How...
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The general solution of the fourth-order differential equation y) + y"+y" = 0 is: y=c_1 +c_2 x+e^((-x)/2) (c_3 cos((V3/2) x)+c_4 sin((v3/2) x) y=c_1 +c_2 x+e^((-x)/2) (c_3 cos((V3) x)+c_4 sin((V3) x) y=c_1 +c_2 x+e^((x)/2) (c_3 cos((v3/2) x)+c_4 sin((V3/2) x) None of them
Transcribed Image Text:The general solution of the fourth-order differential equation y) + y"+y" = 0 is: y=c_1 +c_2 x+e^((-x)/2) (c_3 cos((V3/2) x)+c_4 sin((v3/2) x) y=c_1 +c_2 x+e^((-x)/2) (c_3 cos((V3) x)+c_4 sin((V3) x) y=c_1 +c_2 x+e^((x)/2) (c_3 cos((v3/2) x)+c_4 sin((V3/2) x) None of them
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