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The solution of the differential equation + ytan(z) + y'I sec2 (z) = 0 dz O a. y = ((z² + C) sec2 (z)) O b. y ( + C) sec (z)) Ocy-( (2 +C) sec (z)) d. y = (2 + C) sec (=)) Oe. None of these

The solution of the differential equation + ytan(z) + y'I sec2 (z) = 0 dz O a. y = ((z² + C) sec2 (z)) O b. y ( + C) sec (z)) Ocy-( (2 +C) sec (z)) d. y = (2 + C) sec (=)) Oe. None of these

Calculus: Early Transcendentals
Calculus: Early Transcendentals
8th Edition
ISBN:9781285741550
Author:James Stewart
Publisher:James Stewart
Chapter1: Functions And Models
Section: Chapter Questions
Problem 1RCC: (a) What is a function? What are its domain and range? (b) What is the graph of a function? (c) How...
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The solution of the differential equation + ytan(z) + y³I sec2 (z) = 0 dz O a. y = ((z² + C) sec2 (z)) Oby- ((-* + C) sec (2))* y= (2+C) sec2(z)): OCy-(-(z² + C) sec²(z)) - y = (22 +C) sec2 (z)) e. None of these
Transcribed Image Text:The solution of the differential equation + ytan(z) + y³I sec2 (z) = 0 dz O a. y = ((z² + C) sec2 (z)) Oby- ((-* + C) sec (2))* y= (2+C) sec2(z)): OCy-(-(z² + C) sec²(z)) - y = (22 +C) sec2 (z)) e. None of these
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