The general solution of the fourth-order differential equation y() + y" +y"-0 is: y=c_1 +c_2 x+e^((-x)/2) (c_3 cos((V3/2) x)+c_4 sin((v3/2) x) y=c_1 +c_2 x+e^((-x)/2) (c_3 cos((V3) x)+c_4 sin((v3) x) y=c_1 +c_2 x+e^((x)/2) (c_3 cos((v3/2)
The general solution of the fourth-order differential equation y() + y" +y"-0 is: y=c_1 +c_2 x+e^((-x)/2) (c_3 cos((V3/2) x)+c_4 sin((v3/2) x) y=c_1 +c_2 x+e^((-x)/2) (c_3 cos((V3) x)+c_4 sin((v3) x) y=c_1 +c_2 x+e^((x)/2) (c_3 cos((v3/2)
Calculus: Early Transcendentals
8th Edition
ISBN:9781285741550
Author:James Stewart
Publisher:James Stewart
Chapter1: Functions And Models
Section: Chapter Questions
Problem 1RCC: (a) What is a function? What are its domain and range? (b) What is the graph of a function? (c) How...
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![The general solution of the fourth-order differential equation
y) + y"+y" = 0 is:
y=c_1 +c_2 x+e^((-x)/2) (c_3
cos((V3/2) x)+c_4 sin((v3/2) x)
y=c_1 +c_2 x+e^((-x)/2) (c_3 cos((V3)
x)+c_4 sin((V3) x)
y=c_1 +c_2 x+e^((x)/2) (c_3 cos((v3/2)
x)+c_4 sin((V3/2) x)
None of them](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2F2752ca03-e579-4b8b-b923-91c4435c23c6%2F2c096069-331b-4239-8009-a79254ed3827%2F8tfz85d_processed.jpeg&w=3840&q=75)
Transcribed Image Text:The general solution of the fourth-order differential equation
y) + y"+y" = 0 is:
y=c_1 +c_2 x+e^((-x)/2) (c_3
cos((V3/2) x)+c_4 sin((v3/2) x)
y=c_1 +c_2 x+e^((-x)/2) (c_3 cos((V3)
x)+c_4 sin((V3) x)
y=c_1 +c_2 x+e^((x)/2) (c_3 cos((v3/2)
x)+c_4 sin((V3/2) x)
None of them
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