The general solution for the homogeneous differential equation y(5) – 2y(4) + 2y - 4y" +y - 2y = 0 is? a) y = A+ (B+ Ca) cos a + (D+Ex)sena Ob) y= Axe + (B+ Ca) cos a + (D+ Ex)senz Oc) y = Ae+ (B+ Ca) cos a+ (D+ Ex)senz Od) y= Ae +(B+Ca) cos a + (D+Ex)senr

Calculus: Early Transcendentals
8th Edition
ISBN:9781285741550
Author:James Stewart
Publisher:James Stewart
Chapter1: Functions And Models
Section: Chapter Questions
Problem 1RCC: (a) What is a function? What are its domain and range? (b) What is the graph of a function? (c) How...
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The general solution for the homogeneous differential equation y(5) – 2y(4) + 2y - 4y" + y – 2y = 0
is?
a) y = A+ (B+ Ca) cos a + (D+Ex)sena
Ob) y = Axea + (B+ Ca) cos a+ (D+ Ex)senz
COS
O c) y = Ae2+ (B+Ca²) cos e + (D+ Ex)senz
cos z + (D+ Ex)senz
%3D
Od) y =
= Ae + (B+ Cz) cos a + (D+Ex)senr
Transcribed Image Text:The general solution for the homogeneous differential equation y(5) – 2y(4) + 2y - 4y" + y – 2y = 0 is? a) y = A+ (B+ Ca) cos a + (D+Ex)sena Ob) y = Axea + (B+ Ca) cos a+ (D+ Ex)senz COS O c) y = Ae2+ (B+Ca²) cos e + (D+ Ex)senz cos z + (D+ Ex)senz %3D Od) y = = Ae + (B+ Cz) cos a + (D+Ex)senr
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