The functions y, (t) = t and y2(t) = t are solutions of the homogeneous differential equation ty" – 4ty' + 6y = 0 on (0, o0). To find a solution of the nonhomogeneous differential equation t2y" – 4ty' + 6y = 4t³ on (0, o0), what is the function u(t) of yp = u1(t)t² + u2(t)t? Lütfen birini seçin: -4t² -4t O 4 -4

Advanced Engineering Mathematics
10th Edition
ISBN:9780470458365
Author:Erwin Kreyszig
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Chapter2: Second-order Linear Odes
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The functions y, (t) = t² and y2(t) = t are solutions of the homogeneous differential equation ty" – 4ty' + 6y = 0
on (0, o0). To find a solution of the nonhomogeneous differential equation t2y"– 4ty'+ 6y = 4t³ on (0, o0), what is
the function u(t) of y, = u1(t)t² + u2(t)t?
Lütfen birini seçin:
-4t²
-4t
O 4
-4
Transcribed Image Text:The functions y, (t) = t² and y2(t) = t are solutions of the homogeneous differential equation ty" – 4ty' + 6y = 0 on (0, o0). To find a solution of the nonhomogeneous differential equation t2y"– 4ty'+ 6y = 4t³ on (0, o0), what is the function u(t) of y, = u1(t)t² + u2(t)t? Lütfen birini seçin: -4t² -4t O 4 -4
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