The function V(t)= = - - 3500t+18000, where V is value and t is time in years, can be used to find the value of a large copy machine during the first 5 years of use. a. What is the value of the copier after 3 years and 3 months? After 3 years and 3 months, the copier is worth $ b. What is the salvage value of the copier if it is replaced after 5 years? After 5 years, the salvage value of the copier is S c. State the domain of this function. d. Sketch the graph of this function. 18000+ 1 16000 14000- 12000- 10000 8000+ 6000+ 4000+ 2000- CA Draw sts

Q: 7/3+4/5+1/3=

A: Given: 73+45+13 To find: We have to calculate the value.

Q: 7/13p=-14/11

A:

Q: 4/5 divided by 2/3 =

A: Given that: 4/5 divided by 2/3

Q: 1/3y-9=1/10y

A: Here given as 13y-9=110y Here y is not equal to 0 and 3.

Q: (1. 2) (3.-2) (-1.-2) (4.-3)

A: Integral of a function from a to b= area of the function from x=a to x=b

Q: 24 + 0.44x = 19 + 1.69x

A:

Q: S is 4 years older than J. 8 years ago, s was twice as old than J. What are the ages of S & J?

A: Let the age of S be x years, then the age of J is (x - 4) years, because S is 4 years older than J.

Q: Solve for x. 5. 7.

A:

Q: If =p0.43 and =n100, find X. X =

A: The variable of interest is X.

Q: 0.3 - 0.12x = 0.18x + 0.06

A: Here I am attaching image so that you understand each and every step.

Q: [$3.50 × [1 + (– .122)]]/[.14 – (– .122)] = ?

A:

Q: -1/12 - 1/28

A:

Q: a=109150(1+(-.0261861))^21

A:

Q: 6x 0 < * = 5e

A: we can see from the graph

Q: 5 ( 1.1x + 9 ) = 2 ( -6 - 0.1x )

A: First we solve the bracket and then we rearrange the equation. All the variable are arrange in one…

Q: Solve for X. [1-*-[9] 5X = 6 -8 -6

A:

Q: 1/4 + 1/2 + 3/8 =

A: We need to find sum.

Q: solve for x 4x+1 over 4 minus 2x+3 over 3 equals 7 over 12

A: Given: