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The function f(x) = −2x² + 4x³ 3 has two critical values x = 0, and x = on the interval 2 [-7,7] A) First critical value, x = 0, is A relative minimum, at value f(0): = 0 Neither a relative maximum nor a relative minimum, at value f(0) = 0 A relative maximum, at value f(0) = 0 Not enough information to determine 3 B) Second critical value, x = is 2 Neither a relative maximum nor a relative 3 minimum, at value f 2 = 27 8 A relative minimum, at value f 32 (33) A relative maximum, at value ƒ ( 3 2 Not enough information to determine = 27 8 = 27 8 C) Find the Absolute Maximum: 27 Absolute Maximum is at x = 8 2 N/W 3 27 Absolute Maximum is at x = 2 8 Absolute Maximum is at more than one x values Not enough information to determine D) Find the Absolute Minimum: Absolute Minimum is -6174 at x = -7. Absolute Minimum is at more than one x values Absolute Minimum is -7 at x=-6174. Not enough information to determine

The function f(x) = −2x² + 4x³ 3 has two critical values x = 0, and x = on the interval 2 [-7,7] A) First critical value, x = 0, is A relative minimum, at value f(0): = 0 Neither a relative maximum nor a relative minimum, at value f(0) = 0 A relative maximum, at value f(0) = 0 Not enough information to determine 3 B) Second critical value, x = is 2 Neither a relative maximum nor a relative 3 minimum, at value f 2 = 27 8 A relative minimum, at value f 32 (33) A relative maximum, at value ƒ ( 3 2 Not enough information to determine = 27 8 = 27 8 C) Find the Absolute Maximum: 27 Absolute Maximum is at x = 8 2 N/W 3 27 Absolute Maximum is at x = 2 8 Absolute Maximum is at more than one x values Not enough information to determine D) Find the Absolute Minimum: Absolute Minimum is -6174 at x = -7. Absolute Minimum is at more than one x values Absolute Minimum is -7 at x=-6174. Not enough information to determine

College Algebra (MindTap Course List)
College Algebra (MindTap Course List)
12th Edition
ISBN:9781305652231
Author:R. David Gustafson, Jeff Hughes
Publisher:R. David Gustafson, Jeff Hughes
Chapter4: Polynomial And Rational Functions
Section4.2: Polynomial Functions
Problem 96E: What is the purpose of the Intermediate Value Theorem?
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The function f(x) = −2x² + 4x³ 3 has two critical values x = 0, and x = on the interval 2 [-7,7] A) First critical value, x = 0, is A relative minimum, at value f(0): = 0 Neither a relative maximum nor a relative minimum, at value f(0) = 0 A relative maximum, at value f(0) = 0 Not enough information to determine 3 B) Second critical value, x = is 2 Neither a relative maximum nor a relative 3 minimum, at value f 2 = 27 8 A relative minimum, at value f 32 (33) A relative maximum, at value ƒ ( 3 2 Not enough information to determine = 27 8 = 27 8
Transcribed Image Text:The function f(x) = −2x² + 4x³ 3 has two critical values x = 0, and x = on the interval 2 [-7,7] A) First critical value, x = 0, is A relative minimum, at value f(0): = 0 Neither a relative maximum nor a relative minimum, at value f(0) = 0 A relative maximum, at value f(0) = 0 Not enough information to determine 3 B) Second critical value, x = is 2 Neither a relative maximum nor a relative 3 minimum, at value f 2 = 27 8 A relative minimum, at value f 32 (33) A relative maximum, at value ƒ ( 3 2 Not enough information to determine = 27 8 = 27 8
C) Find the Absolute Maximum: 27 Absolute Maximum is at x = 8 2 N/W 3 27 Absolute Maximum is at x = 2 8 Absolute Maximum is at more than one x values Not enough information to determine D) Find the Absolute Minimum: Absolute Minimum is -6174 at x = -7. Absolute Minimum is at more than one x values Absolute Minimum is -7 at x=-6174. Not enough information to determine
Transcribed Image Text:C) Find the Absolute Maximum: 27 Absolute Maximum is at x = 8 2 N/W 3 27 Absolute Maximum is at x = 2 8 Absolute Maximum is at more than one x values Not enough information to determine D) Find the Absolute Minimum: Absolute Minimum is -6174 at x = -7. Absolute Minimum is at more than one x values Absolute Minimum is -7 at x=-6174. Not enough information to determine
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