P(t) = 1² (1² + 1)5/2 p'(t) = t² . — ±√(t² + 1)³/2 . 2t + 2t(t² + 1)5/2 . = 5t³ (1² + 1)³/2 + 21(1² + 1)5/2 =t(t² + 1)³/2 [51² + 2(1² + 1)'] = 1(1² + 1)³/² (71² + 2) y = −6e2x dy dx = -6(2e2x) = −12e²x
P(t) = 1² (1² + 1)5/2 p'(t) = t² . — ±√(t² + 1)³/2 . 2t + 2t(t² + 1)5/2 . = 5t³ (1² + 1)³/2 + 21(1² + 1)5/2 =t(t² + 1)³/2 [51² + 2(1² + 1)'] = 1(1² + 1)³/² (71² + 2) y = −6e2x dy dx = -6(2e2x) = −12e²x
Algebra & Trigonometry with Analytic Geometry
13th Edition
ISBN:9781133382119
Author:Swokowski
Publisher:Swokowski
Chapter5: Inverse, Exponential, And Logarithmic Functions
Section: Chapter Questions
Problem 43RE
Related questions
Question
Explain step by step of how they got to the answer for both problems
![P(t) = 1² (1² + 1)5/2
p'(t) = t² . — ±√(t² + 1)³/2 . 2t + 2t(t² + 1)5/2
.
= 5t³ (1² + 1)³/2 + 21(1² + 1)5/2
=t(t² + 1)³/2 [51² + 2(1² + 1)']
= 1(1² + 1)³/² (71² + 2)
y = −6e2x
dy
dx
=
-6(2e2x) = −12e²x](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2F41a94607-ae05-49d2-a989-bd66a70c4a42%2F98e17122-dd9d-48d5-8eb6-0a6d9b0ffaa1%2Fmyvfks_processed.jpeg&w=3840&q=75)
Transcribed Image Text:P(t) = 1² (1² + 1)5/2
p'(t) = t² . — ±√(t² + 1)³/2 . 2t + 2t(t² + 1)5/2
.
= 5t³ (1² + 1)³/2 + 21(1² + 1)5/2
=t(t² + 1)³/2 [51² + 2(1² + 1)']
= 1(1² + 1)³/² (71² + 2)
y = −6e2x
dy
dx
=
-6(2e2x) = −12e²x
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