The frontal working area of the electrode in an ECM operation is 2000 mm2. The applied current is 2000 amps and the voltage is 12 volts. The material being cut is nickel (valence = 2, CNi =3.42x10-2mm/A-s). (a) If the process is 90% efficient, determine the cutting rate into the workpart. (b) If the resistivity of the electrolyte is 160 ohm – mm, determine the working gap. Tool feed Tool holder and
The frontal working area of the electrode in an ECM operation is 2000 mm2. The applied current is 2000 amps and the voltage is 12 volts. The material being cut is nickel (valence = 2, CNi =3.42x10-2mm/A-s). (a) If the process is 90% efficient, determine the cutting rate into the workpart. (b) If the resistivity of the electrolyte is 160 ohm – mm, determine the working gap. Tool feed Tool holder and
Elements Of Electromagnetics
7th Edition
ISBN:9780190698614
Author:Sadiku, Matthew N. O.
Publisher:Sadiku, Matthew N. O.
ChapterMA: Math Assessment
Section: Chapter Questions
Problem 1.1MA
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Transcribed Image Text:The frontal working area of the electrode in an ECM operation is 2000 mm?. The applied current is 2000 amps
and the voltage is 12 volts. The material being cut is nickel (valence = 2, CN; =3.42x10-2mm2/A-s). (a) If the
process is 90% efficient, determine the cutting rate into the workpart. (b) If the resistivity of the electrolyte is
160 ohm – mm, determine the working gap.
Tool feed
Tool holder and
feed mechanism
Formed tool (cathode).
Electrolyte flow
-Insulation
Electrolyte
Work (anode)
feed
mm/min
gap
micrometers
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