The freezing point of ethanol (C2H§OH) is -114.6 °C. The molal freezing point depression constant for ethanol is 2.00 °C/m. What is the freezing point (°C) of a solution prepared by dissolving 59.1 g of glycerin (C3HgO3, a nonelectrolyte) in 400.0 g of ethanol? The molar mass of ethanol is 46.068 g/mol. Enter your answer with 1 decimal place and no unit.

Chemistry
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Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
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### Freezing Point Depression in Solutions

**Problem Statement:**

The freezing point of ethanol (C₂H₅OH) is -114.6 °C. The molal freezing point depression constant (Kf) for ethanol is 2.00 °C/m. Calculate the freezing point (°C) of a solution prepared by dissolving 59.1 g of glycerin (C₃H₈O₃, a nonelectrolyte) in 400.0 g of ethanol.

The molar mass of ethanol is 46.068 g/mol.

**Solution Requirements:**

To solve this problem, follow these steps:

1. **Calculate the molality of the solution:**
   - Molality (m) is defined as the moles of solute (glycerin) per kilogram of solvent (ethanol).
   - Number of moles of glycerin can be found using its molecular weight.

2. **Determine the freezing point depression:**
   - Use the formula \(\Delta T_f = K_f \times m\), where \(\Delta T_f\) is the freezing point depression.

3. **Calculate the new freezing point:**
   - Subtract the freezing point depression from the pure solvent's freezing point.

**Enter your answer with 1 decimal place and no unit.**

**Answer:**
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Transcribed Image Text:### Freezing Point Depression in Solutions **Problem Statement:** The freezing point of ethanol (C₂H₅OH) is -114.6 °C. The molal freezing point depression constant (Kf) for ethanol is 2.00 °C/m. Calculate the freezing point (°C) of a solution prepared by dissolving 59.1 g of glycerin (C₃H₈O₃, a nonelectrolyte) in 400.0 g of ethanol. The molar mass of ethanol is 46.068 g/mol. **Solution Requirements:** To solve this problem, follow these steps: 1. **Calculate the molality of the solution:** - Molality (m) is defined as the moles of solute (glycerin) per kilogram of solvent (ethanol). - Number of moles of glycerin can be found using its molecular weight. 2. **Determine the freezing point depression:** - Use the formula \(\Delta T_f = K_f \times m\), where \(\Delta T_f\) is the freezing point depression. 3. **Calculate the new freezing point:** - Subtract the freezing point depression from the pure solvent's freezing point. **Enter your answer with 1 decimal place and no unit.** **Answer:** ``` [ ] ```
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