The free energy change for the following reaction at 25 °C, when [Co2+] = 3.37×10-3 M and [Cu2+] =1.17 M, is 98.1 kJ: %3D Co2*(3.37×103 M) + 2Cu*(aq)- →Co(s) + 2Cu2*(1.17 M) AG = 98.1 kJ What is the cell potential for the reaction as written under these conditions? Answer: V Would this reaction be spontaneous in the forward or the reverse direction?
The free energy change for the following reaction at 25 °C, when [Co2+] = 3.37×10-3 M and [Cu2+] =1.17 M, is 98.1 kJ: %3D Co2*(3.37×103 M) + 2Cu*(aq)- →Co(s) + 2Cu2*(1.17 M) AG = 98.1 kJ What is the cell potential for the reaction as written under these conditions? Answer: V Would this reaction be spontaneous in the forward or the reverse direction?
Chemistry
10th Edition
ISBN:9781305957404
Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Publisher:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Chapter1: Chemical Foundations
Section: Chapter Questions
Problem 1RQ: Define and explain the differences between the following terms. a. law and theory b. theory and...
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![The free energy change for the following reaction at 25 °C, when [Co2+] = 3.37×10-3 M and [Cu2+] =1.17 M, is 98.1 kJ:
%3D
Co2*(3.37×103 M) + 2Cu*(aq)-
→Co(s) + 2Cu2*(1.17 M)
AG = 98.1 kJ
What is the cell potential for the reaction as written under these conditions?
Answer:
V
Would this reaction be spontaneous in the forward or the reverse direction?](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2F040a94ea-265d-4fab-9395-230495326c1d%2F40af1eef-e116-4140-a773-857025da90e4%2Fcl3bs39.png&w=3840&q=75)
Transcribed Image Text:The free energy change for the following reaction at 25 °C, when [Co2+] = 3.37×10-3 M and [Cu2+] =1.17 M, is 98.1 kJ:
%3D
Co2*(3.37×103 M) + 2Cu*(aq)-
→Co(s) + 2Cu2*(1.17 M)
AG = 98.1 kJ
What is the cell potential for the reaction as written under these conditions?
Answer:
V
Would this reaction be spontaneous in the forward or the reverse direction?
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