The Fourier Transform of a piecewise smooth function f(x), for which f(x)|dx exists and is finite, is given by 1 F(k) =F[f(x)] = = 2πT √2 f(x)e-ik² dr. In particular we have F(ak) = ¼Ƒ[ƒ(4)] and F[e¯³] = e. Consider the differential equation u₁ = tuxx -xx<∞, subject to initial condition u(x, 0) = e− Defining (k,t) = F[u(x, t)] (1+t2)k2\ û(k,t) = exp 2 (4) (5) Show that the solution of equation (4) satisfying the initial condition (5) has the form 1 u(x,t) = = exp 1+t2 (-2 x² 2(1+t2)

Advanced Engineering Mathematics
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ISBN:9780470458365
Author:Erwin Kreyszig
Publisher:Erwin Kreyszig
Chapter2: Second-order Linear Odes
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The Fourier Transform of a piecewise smooth function f(x), for which |f(x)|dx
exists and is finite, is given by
1
F(k) =F[f(x)] =
=
√2 f(x)e-ik² dr.
2πT
In particular we have F(ak) = ¼Ƒ[ƒ(4)] and F[e¯½³] = e.
Consider the differential equation
u₁ = tuxx
-8<x<∞,
subject to initial condition
u(x, 0) = e−².
Defining (k,t) = F[u(x, t)]
(1+t2)k2\
û(k,t) = exp
2
(4)
(5)
Show that the solution of equation (4) satisfying the initial condition (5) has
the form
1
u(x,t) =
=
exp
1+t2
(-2
x²
2(1+t2)
Transcribed Image Text:The Fourier Transform of a piecewise smooth function f(x), for which |f(x)|dx exists and is finite, is given by 1 F(k) =F[f(x)] = = √2 f(x)e-ik² dr. 2πT In particular we have F(ak) = ¼Ƒ[ƒ(4)] and F[e¯½³] = e. Consider the differential equation u₁ = tuxx -8<x<∞, subject to initial condition u(x, 0) = e−². Defining (k,t) = F[u(x, t)] (1+t2)k2\ û(k,t) = exp 2 (4) (5) Show that the solution of equation (4) satisfying the initial condition (5) has the form 1 u(x,t) = = exp 1+t2 (-2 x² 2(1+t2)
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