The formula used to calculate a confidence interval for the mean of a normal population when in is small is the following.(t critical value)What is the appropriate t critical value for each of the following confidence levels and sample sizes? (Round your answers to two decimal places.)LUSE SALT(a) 95% confidence, n = 17(b) 90% confidence, n = 11(c) 99% confidence, n = 24(d) 90% confidence, n = 25(e) 80% confidence, n = 13(f) 95% confidence, n = 9

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MATLAB: An Introduction with Applications

6th Edition

ISBN:9781119256830

Author:Amos Gilat

Publisher:Amos Gilat

Chapter1: Starting With Matlab

Section: Chapter Questions

Problem 1P

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Use technology to construct the confidence intervals for the population variance o? and the population standard deviation o. Assume the sample is taken from a normally distributed population. c= 0.99, s= 37, n 20 The confidence interval for the population variance is (Round to two decimal places as needed.) The confidence interval for the population standard deviation is (Round to two decimal places as needed.)
the distribution of scores on a standardized test is approximately Normal with standard deviation of σ = 21. If a sample of 135 students had a mean score of x¯ = 73.6, use this to find a 99% confidence interval for the mean score of all students on this test. We are 99% confident that the the mean score of students on this test was in the interval ______ to _____. What is the margin of error for your confidence interval? Margin of error =
The distribution of scores ona standardized test is approximately Normal with standard deviation of 14. If a sample of 75 students had a mean score of 75.8, use this to find 99% confidence interval for the mean score of all students on this test. we are 99% confident that the mean score of students on this test was in the interval ______ to _______ what is the margin of error for your confidence interval? margin of error=
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Calculate the margin of error and construct the confidence interval for the population mean using the Student's t- distribution (you may assume the population data is normally distributed). T-Distribution Table a. x=85.3, n=64, s=16.5, 99% confidence E== Round to two decimal places if necessary <#< Round to two decimal places if necessary
Mm
Which confidence interval would lead you to Fail to Reject H0? Group of answer choices Test value: 10 Confidence Interval: 13.1 – 15.1 Test value: 5 Confidence Interval: 5.6 – 6.9 Test value: 5 Confidence Interval: 4.5 – 6.3 Test value: 10 Confidence Interval: 9.2 – 9.8
A sample mean, sample size, population standard deviation, and confidence level are provided. Use this information to complete parts (a) through (c) below. x=35, n=27, σ=5 confidence level=90% a. Use the one-mean z-interval procedure to find a confidence interval for the mean of the population from which the sample was drawn. The confidence interval is from _______ to _________. (Type integers or decimals rounded to one decimal place as needed.) b. Obtain the margin of error by taking half the length of the confidence interval. What is the length of the confidence interval? ____________ (Type an integer or decimal rounded to one decimal place as needed.) c. Obtain the margin of error by using the formula E=zα2•σn. Identify the critical value. zα2=____________ (Type an integer or decimal rounded to two decimal places as needed.) What is the margin of error obtained using the methods of parts (b) and(c)? _________ (Type an integer or decimal…
W: 6.1 & 6.2 16 K Question 14, 6.1.35 Part 1 of 3 HW Score: 47.14%, 16.5 of 35 points O Points: 0 of 1 Save You are given the sample mean and the population standard deviation. Use this information to construct the 90% and 95% confidence intervals for the population mean. Interpret the results and compare the widths of the confidence intervals. If convenient, use technology to construct the confidence intervals. A random sample of 55 home theater systems has a mean price of $119.00. Assume the population standard deviation is $16.30. Construct a 90% confidence interval for the population mean. The 90% confidence interval is (D). (Round to two decimal places as needed.) e solve this View an example Get more help - sty cloudy N 40+ # Q Search % 0+ A 0 6 7 28 & 8 9 0 Clear all Delete Backspace Lock 10.00 PM 4372024 7 Home CO 6 PgUp
You are interested in finding a 95% confidence interval for the average number of days of class that college students miss each year. The data below show the number of missed days for 13 randomly selected college students. Round answers to 3 decimal places where possible. 7 5 3 9 11 6 4 12 0 6 0 6 2 With 95% confidence the population mean number of days of class that college students miss is between ------- and ----------- days.

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