The formula used to calculate a confidence interval for the mean of a normal population when n is small is the following.X ± (t critical value)What is the appropriate t critical value for each of the following confidence levels and sample sizes? (Round your answers totwo decimal places.)(a) 90% confidence, n = 171.75(b) 90% confidence, n = 131.78(c) 99% confidence, n = 242.81(d) 90% confidence, n = 23(e) 80% confidence, n = 13S(f) 95% confidence, n = 9

The question is about t critical value Introduction The critical value is the value of the test stat…

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MATLAB: An Introduction with Applications

6th Edition

ISBN:9781119256830

Author:Amos Gilat

Publisher:Amos Gilat

Chapter1: Starting With Matlab

Section: Chapter Questions

Problem 1P

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Use technology to construct the confidence intervals for the population variance o? and the population standard deviation o. Assume the sample is taken from a normally distributed population. c= 0.99, s= 37, n 20 The confidence interval for the population variance is (Round to two decimal places as needed.) The confidence interval for the population standard deviation is (Round to two decimal places as needed.)
Ages of students: A simple random sample of 110 U.S. college students had a mean age of 23.05 years. Assume the population standard deviation is o =4.81 years. Construct a 90% confidence interval for the mean age of U.S. college students. Round the answers to two decimal places. A 90% confidence interval for the mean age of U.S. college students is 22.46 T< u <23.64
the distribution of scores on a standardized test is approximately Normal with standard deviation of σ = 21. If a sample of 135 students had a mean score of x¯ = 73.6, use this to find a 99% confidence interval for the mean score of all students on this test. We are 99% confident that the the mean score of students on this test was in the interval ______ to _____. What is the margin of error for your confidence interval? Margin of error =
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Use technology to construct the confidence intervals for the population variance o2 and the population standard deviation o. Assume the sample is taken from a normally distributed population. c= 0.95, s= 34, n= 17 ..... The confidence interval for the population variance is (Round to two decimal places as needed.)
es A sample of 12 fossil skeletons of an extinct species of bird has been collected. The mean length of the skulls in this sample is 5.29 cm and the standard deviation of the sample is 0.21 cm. Assuming that such measurements are normally distributed, find a 90% confidence interval for the population mean length of the skulls of this species of bird. You may want to use one of these: qt (p-0.10, df-11, lower. tail-FALSE)=1.36343 qt(p-0.05, df-11, lower.tail-FALSE) =1.795885 qnorm(0.10, mean-0, sd-1, lower.tail-FALSE)=1.281552 qnorm(0.05, mean-0, sd-1, lower.tail=FALSE)=1.644854 O (4.945, 5.635) O (4.913, 5.667) O (5.021, 5.559) O (5.181, 5.399)
(1 point) A random sample of 70 observations produced a mean of a 39.5 from a population with a normal distribution and a standard deviation o = 2.14. (a) Find a 95% confidence interval for u (b) Find a 99% confidence interval for (c) Find a 90% confidence interval for
You want to obtain a sample to estimate a population mean. Based on previous evidence, you believe the population standard deviation is approximately o = 74.4. You would like to be 90% confident that your estimate is within 4 of the true population mean. How large of a sample size is required? n=
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Use the T Table to find the T score that corresponds to a sample size of 15 and a confidence level of 95% (? = 0.05) for a two-tail distribution. (A) 1.761 (B) 2.131 (C) 2.145 (D) 2.030
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